OCR S3 2015 June — Question 1 6 marks

Exam BoardOCR
ModuleS3 (Statistics 3)
Year2015
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLinear combinations of normal random variables
TypeAll components random including container
DifficultyModerate -0.8 This is a straightforward application of standard results for linear combinations of independent normal random variables. Part (i) requires only direct use of formulas for mean and variance of sums (E[aX+bY]=aE[X]+bE[Y] and Var[aX+bY]=a²Var[X]+b²Var[Y]), while part (ii) involves a routine inverse normal calculation using tables or calculator. No problem-solving insight or novel reasoning is required—purely mechanical application of learned techniques.
Spec5.04b Linear combinations: of normal distributions

1 A laminate consists of 4 layers of material \(C\) and 3 layers of material \(D\). The thickness of a layer of material \(C\) has a normal distribution with mean 1 mm and standard deviation 0.1 mm , and the thickness of a layer of material \(D\) has a normal distribution with mean 8 mm and standard deviation 0.2 mm . The layers are independent of one another.
  1. Find the mean and variance of the total thickness of the laminate.
  2. What total thickness is exceeded by \(1 \%\) of the laminates?

Question 1:
Part (i)
AnswerMarks Guidance
AnswerMarks Guidance
28B1
\(4 \times 0.1^2 + 3 \times 0.2^2\)M1 Not \(4^2\), \(3^2\)
0.16A1
Part (ii)
AnswerMarks Guidance
AnswerMarks Guidance
\(\frac{x - \text{"28"}}{\sqrt{\text{"0.16"}}}\)M1
\(= 2.326\)B1
28.9A1
## Question 1:

### Part (i)
| Answer | Marks | Guidance |
|--------|-------|----------|
| 28 | B1 | |
| $4 \times 0.1^2 + 3 \times 0.2^2$ | M1 | Not $4^2$, $3^2$ |
| 0.16 | A1 | |

### Part (ii)
| Answer | Marks | Guidance |
|--------|-------|----------|
| $\frac{x - \text{"28"}}{\sqrt{\text{"0.16"}}}$ | M1 | |
| $= 2.326$ | B1 | |
| 28.9 | A1 | |

---
1 A laminate consists of 4 layers of material $C$ and 3 layers of material $D$. The thickness of a layer of material $C$ has a normal distribution with mean 1 mm and standard deviation 0.1 mm , and the thickness of a layer of material $D$ has a normal distribution with mean 8 mm and standard deviation 0.2 mm . The layers are independent of one another.\\
(i) Find the mean and variance of the total thickness of the laminate.\\
(ii) What total thickness is exceeded by $1 \%$ of the laminates?

\hfill \mbox{\textit{OCR S3 2015 Q1 [6]}}