Edexcel AEA 2012 June — Question 3 10 marks

Exam BoardEdexcel
ModuleAEA (Advanced Extension Award)
Year2012
SessionJune
Marks10
PaperDownload PDF ↗
TopicAddition & Double Angle Formulae
TypeTwo angles with tan relationships
DifficultyHard +2.3 This AEA question requires recognizing a geometric series, applying the sum formula, manipulating the resulting equation using double angle formulae (tan 2θ = 2tan θ/(1-tan²θ)), and solving a quartic equation in tan θ. The multi-step algebraic manipulation and the need to connect the solution to angle bounds makes this significantly harder than standard A-level trigonometry questions.
Spec1.04j Sum to infinity: convergent geometric series |r|<11.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.06g Equations with exponentials: solve a^x = b

3.The angle \(\theta , 0 < \theta < \frac { \pi } { 2 }\) ,satisfies $$\tan \theta \tan 2 \theta = \sum _ { r = 0 } ^ { \infty } 2 \cos ^ { r } 2 \theta$$
  1. Show that \(\tan \theta = 3 ^ { p }\) ,where \(p\) is a rational number to be found.
  2. Hence show that \(\frac { \pi } { 6 } < \theta < \frac { \pi } { 4 }\)

3.The angle $\theta , 0 < \theta < \frac { \pi } { 2 }$ ,satisfies

$$\tan \theta \tan 2 \theta = \sum _ { r = 0 } ^ { \infty } 2 \cos ^ { r } 2 \theta$$
\begin{enumerate}[label=(\alph*)]
\item Show that $\tan \theta = 3 ^ { p }$ ,where $p$ is a rational number to be found.
\item Hence show that $\frac { \pi } { 6 } < \theta < \frac { \pi } { 4 }$
\end{enumerate}

\hfill \mbox{\textit{Edexcel AEA 2012 Q3 [10]}}