OCR MEI C4 — Question 5 7 marks

Exam BoardOCR MEI
ModuleC4 (Core Mathematics 4)
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHarmonic Form
TypeExpress and solve equation
DifficultyStandard +0.3 This is a standard two-part harmonic form question requiring routine application of the R cos(θ + α) formula to find R and α, followed by solving a straightforward trigonometric equation. While it involves multiple steps, both parts follow well-practiced procedures with no novel insight required, making it slightly easier than average.
Spec1.05n Harmonic form: a sin(x)+b cos(x) = R sin(x+alpha) etc1.05o Trigonometric equations: solve in given intervals

5 Express \(4 \cos \theta - \sin \theta\) in the form \(R \cos ( \theta + \alpha )\), where \(R > 0\) and \(0 < \alpha < \frac { 1 } { 2 } \pi\).
Hence solve the equation \(4 \cos \theta - \sin \theta = 3\), for \(0 \leqslant \theta \leqslant 2 \pi\).

Question 5:
AnswerMarks Guidance
\(4\cos\theta - \sin\theta = R\cos(\theta + \alpha) = R(\cos\theta\cos\alpha - R\sin\theta\sin\alpha)\)M1 \(R\cos\): correct pairs
\(R\cos\alpha = 4\), \(R\sin\alpha = 1\)B1 \(R = \sqrt{17} = 4.123\)
\(R^2 = 1^2 + 4^2 = 17\), \(R = \sqrt{17} = 4.123\)M1 \(\tan\alpha = \frac{1}{4}\) o.e.
\(\tan\alpha = \frac{1}{4}\)A1 \(\alpha = 0.245\)
\(\Rightarrow \alpha = 0.245\)
\(\sqrt{17}\cos(\theta + 0.245) = 3\)
\(\cos(\theta + 0.245) = \frac{3}{\sqrt{17}}\)M1 \(\theta + 0.245 = \arccos\frac{3}{\sqrt{17}}\), ft their \(R\), \(\alpha\) for method
\(\theta + 0.245 = 0.756, 5.527\)
\(\theta = 0.511, 5.282\)A1 A1 (penalise extra solutions in the range \((-1)\))
## Question 5:

$4\cos\theta - \sin\theta = R\cos(\theta + \alpha) = R(\cos\theta\cos\alpha - R\sin\theta\sin\alpha)$ | M1 | $R\cos$: correct pairs |

$R\cos\alpha = 4$, $R\sin\alpha = 1$ | B1 | $R = \sqrt{17} = 4.123$ |

$R^2 = 1^2 + 4^2 = 17$, $R = \sqrt{17} = 4.123$ | M1 | $\tan\alpha = \frac{1}{4}$ o.e. |

$\tan\alpha = \frac{1}{4}$ | A1 | $\alpha = 0.245$ |

$\Rightarrow \alpha = 0.245$ | | |

$\sqrt{17}\cos(\theta + 0.245) = 3$ | | |

$\cos(\theta + 0.245) = \frac{3}{\sqrt{17}}$ | M1 | $\theta + 0.245 = \arccos\frac{3}{\sqrt{17}}$, ft their $R$, $\alpha$ for method |

$\theta + 0.245 = 0.756, 5.527$ | | |

$\theta = 0.511, 5.282$ | A1 A1 | (penalise extra solutions in the range $(-1)$) |
5 Express $4 \cos \theta - \sin \theta$ in the form $R \cos ( \theta + \alpha )$, where $R > 0$ and $0 < \alpha < \frac { 1 } { 2 } \pi$.\\
Hence solve the equation $4 \cos \theta - \sin \theta = 3$, for $0 \leqslant \theta \leqslant 2 \pi$.

\hfill \mbox{\textit{OCR MEI C4  Q5 [7]}}