OCR MEI C4 — Question 2 7 marks

Exam BoardOCR MEI
ModuleC4 (Core Mathematics 4)
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHarmonic Form
TypeExpress and solve equation
DifficultyModerate -0.3 This is a standard harmonic form question with routine application of R cos(θ-α) expansion and solving. Finding R=5 and α=arctan(4/3) requires basic trigonometric identities, then solving R cos(θ-α)=2 is straightforward. Slightly easier than average due to being a textbook-standard procedure with no conceptual challenges.
Spec1.05n Harmonic form: a sin(x)+b cos(x) = R sin(x+alpha) etc1.05o Trigonometric equations: solve in given intervals

2 Express \(3 \cos \theta + 4 \sin \theta\) in the form \(R \cos ( \theta - \alpha )\), where \(R > 0\) and \(0 < \alpha < \frac { - \pi } { 2 }\).
Hence solve the equation \(3 \cos \theta + 4 \sin \theta = 2\) for \(\quad - \pi \leqslant \theta \leqslant \pi\).

Question 2:
AnswerMarks Guidance
\(3\cos\theta + 4\sin\theta = R\cos(\theta - \alpha) = R(\cos\theta\cos\alpha + \sin\theta\sin\alpha)\)M1
\(R\cos\alpha = 3\), \(R\sin\alpha = 4\)B1
\(R^2 = 3^2 + 4^2 = 25 \Rightarrow R = 5\)M1A1 \(R = 5\) cwo
\(\tan\alpha = \frac{4}{3} \Rightarrow \alpha = 0.9273\)
\(5\cos(\theta - 0.9273) = 2\)M1
\(\cos(\theta - 0.9273) = \frac{2}{5}\)
\(\theta - 0.9273 = 1.1593, -1.1593\)A1 A1 and no others in the range
\(\theta = 2.087, -0.232\)
## Question 2:

$3\cos\theta + 4\sin\theta = R\cos(\theta - \alpha) = R(\cos\theta\cos\alpha + \sin\theta\sin\alpha)$ | M1 | |

$R\cos\alpha = 3$, $R\sin\alpha = 4$ | B1 | |

$R^2 = 3^2 + 4^2 = 25 \Rightarrow R = 5$ | M1A1 | $R = 5$ cwo |

$\tan\alpha = \frac{4}{3} \Rightarrow \alpha = 0.9273$ | | |

$5\cos(\theta - 0.9273) = 2$ | M1 | |

$\cos(\theta - 0.9273) = \frac{2}{5}$ | | |

$\theta - 0.9273 = 1.1593, -1.1593$ | A1 A1 | and no others in the range |

$\theta = 2.087, -0.232$ | | |

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2 Express $3 \cos \theta + 4 \sin \theta$ in the form $R \cos ( \theta - \alpha )$, where $R > 0$ and $0 < \alpha < \frac { - \pi } { 2 }$.\\
Hence solve the equation $3 \cos \theta + 4 \sin \theta = 2$ for $\quad - \pi \leqslant \theta \leqslant \pi$.

\hfill \mbox{\textit{OCR MEI C4  Q2 [7]}}