OCR FP1 Specimen — Question 3 8 marks

Exam BoardOCR
ModuleFP1 (Further Pure Mathematics 1)
SessionSpecimen
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComplex Numbers Arithmetic
TypeMultiplication and powers of complex numbers
DifficultyModerate -0.3 This is a standard Further Pure 1 question testing basic complex number operations: squaring a complex number, simplifying expressions, and rationalizing a complex fraction. All parts use routine techniques with no novel insight required. While it's Further Maths content, these are foundational FP1 skills, making it slightly easier than an average A-level question overall.
Spec4.02a Complex numbers: real/imaginary parts, modulus, argument4.02e Arithmetic of complex numbers: add, subtract, multiply, divide

3 The complex number \(2 + \mathrm { i }\) is denoted by \(z\), and the complex conjugate of \(z\) is denoted by \(z ^ { * }\).
  1. Express \(z ^ { 2 }\) in the form \(x + \mathrm { i } y\), where \(x\) and \(y\) are real, showing clearly how you obtain your answer.
  2. Show that \(4 z - z ^ { 2 }\) simplifies to a real number, and verify that this real number is equal to \(z z ^ { * }\).
  3. Express \(\frac { z + 1 } { z - 1 }\) in the form \(x + \mathrm { i } y\), where \(x\) and \(y\) are real, showing clearly how you obtain your answer.

AnswerMarks Guidance
(i) \(z^2 = (2+i)^2 = 4 + 4i + i^2 = 3 + 4i\)M1, A1 For showing 3-term or 4-term expansion / For correct answer
Total: 2 marks
(ii) \(4z - z^2 = 8 + 4i - 3 - 4i = 5\)
AnswerMarks Guidance
\(zz^* = (2+i)(2-i) = 5\)B1, B1, B1 For correct value 5 / For stating or using \(z^* = 2-i\) / For correct verification of given result
Total: 3 marks
AnswerMarks Guidance
(iii) \(\frac{z+1}{z-1} = \frac{3+i}{1+i} = \frac{(3+i)(1-i)}{(1+i)(1-i)} = \frac{4-2i}{2} = 2-i\)B1, M1, A1 For correct initial form / For multiplying top and bottom by \(1-i\) / For correct answer \(2-i\)
Total: 3 marks
Question 3 Total: 8 marks
**(i)** $z^2 = (2+i)^2 = 4 + 4i + i^2 = 3 + 4i$ | M1, A1 | For showing 3-term or 4-term expansion / For correct answer

**Total: 2 marks**

**(ii)** $4z - z^2 = 8 + 4i - 3 - 4i = 5$
$zz^* = (2+i)(2-i) = 5$ | B1, B1, B1 | For correct value 5 / For stating or using $z^* = 2-i$ / For correct verification of given result

**Total: 3 marks**

**(iii)** $\frac{z+1}{z-1} = \frac{3+i}{1+i} = \frac{(3+i)(1-i)}{(1+i)(1-i)} = \frac{4-2i}{2} = 2-i$ | B1, M1, A1 | For correct initial form / For multiplying top and bottom by $1-i$ / For correct answer $2-i$

**Total: 3 marks**

**Question 3 Total: 8 marks**

---
3 The complex number $2 + \mathrm { i }$ is denoted by $z$, and the complex conjugate of $z$ is denoted by $z ^ { * }$.\\
(i) Express $z ^ { 2 }$ in the form $x + \mathrm { i } y$, where $x$ and $y$ are real, showing clearly how you obtain your answer.\\
(ii) Show that $4 z - z ^ { 2 }$ simplifies to a real number, and verify that this real number is equal to $z z ^ { * }$.\\
(iii) Express $\frac { z + 1 } { z - 1 }$ in the form $x + \mathrm { i } y$, where $x$ and $y$ are real, showing clearly how you obtain your answer.

\hfill \mbox{\textit{OCR FP1  Q3 [8]}}