OCR MEI C2 — Question 9 3 marks

Exam BoardOCR MEI
ModuleC2 (Core Mathematics 2)
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTrigonometric equations in context
TypeExact value from special triangle
DifficultyEasy -1.8 This is a straightforward geometric proof using a standard equilateral triangle with basic Pythagoras. It requires only recall of the definition of sine and one simple calculation - significantly easier than average A-level questions which typically involve multi-step problem-solving.
Spec1.05g Exact trigonometric values: for standard angles1.05m Geometric proofs: of trig sum and double angle formulae
9 Fig. 3 Beginning with the triangle shown in Fig. 3, prove that \(\sin 60 ^ { \circ } = \frac { \sqrt { 3 } } { 2 }\).
Question 9:
AnswerMarks
Triangle divided into 2 right-angled trianglesH1
\(\sqrt{3}\) and 1 indicatedS1
60 indicatedA1
Total: 3 marks
Question 9:

Triangle divided into 2 right-angled triangles | H1

$\sqrt{3}$ and 1 indicated | S1

60 indicated | A1

**Total: 3 marks**
9

Fig. 3

Beginning with the triangle shown in Fig. 3, prove that $\sin 60 ^ { \circ } = \frac { \sqrt { 3 } } { 2 }$.

\hfill \mbox{\textit{OCR MEI C2  Q9 [3]}}
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Q1 3 Q2 5 Q3 5 Q4 5 Q5 3 Q6 3 Q7 3 Q8 3 Q9 3 Q10 5 Q11 5 Q12 5