| Exam Board | OCR MEI |
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| Module | C2 (Core Mathematics 2) |
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| Topic | Trig Equations |
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3 Show that the equation \(4 \cos ^ { 2 } \theta = 1 + \sin \theta\) can be expressed as
$$4 \sin ^ { 2 } \theta + \sin \theta - 3 = 0$$
Hence solve the equation for \(0 ^ { \circ } \leqslant \theta \leqslant 360 ^ { \circ }\).