OCR MEI C2 — Question 4 11 marks

Exam BoardOCR MEI
ModuleC2 (Core Mathematics 2)
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStationary points and optimisation
TypeFind stationary point then sketch curve
DifficultyModerate -0.8 This is a straightforward C2 question testing routine differentiation and stationary point analysis. Part (i) requires basic polynomial differentiation and solving a quadratic, part (ii) involves factorising a cubic, and part (iii) is a standard sketch. All techniques are textbook exercises with no problem-solving insight required, making it easier than average.
Spec1.02n Sketch curves: simple equations including polynomials1.07n Stationary points: find maxima, minima using derivatives

4
  1. Differentiate \(x ^ { 3 } - 3 x ^ { 2 } - 9 x\). Hence find the \(x\)-coordinates of the stationary points on the curve \(y = x ^ { 3 } - 3 x ^ { 2 } - 9 x\), showing which is the maximum and which the minimum.
  2. Find, in exact form, the coordinates of the points at which the curve crosses the \(x\)-axis.
  3. Sketch the curve.

Question 4:
Part i:
AnswerMarks Guidance
\(y'=6x^2-18x+12\)M1 condone one error
\(=12\)M1 subst of \(x=3\) in their \(y'\)
\(y=7\) when \(x=3\)B1
tgt is \(y-7=12(x-3)\)M1 f.t. their \(y\) and \(y'\)
verifying \((-1,-41)\) on tgtA1 or B2 for showing line joining \((3,7)\) and \((-1,-41)\) has gradient 12
Part ii:
AnswerMarks Guidance
\(y'=0\) s.o.i.M1 Their \(y'\)
quadratic with 3 termsM1 Any valid attempt at solution
\(x=1\) or \(2\)A1 or A1 for \((1,3)\) and A1 for \((2,2)\) marking to benefit of candidate
\(y=3\) or \(2\)A1
Part iii:
AnswerMarks Guidance
cubic curve correct orientation touching \(x\)-axis only at \((0.2,0)\)G1
max and min correctG1 f.
curve crossing \(y\)-axis only at \(-2\)G1
## Question 4:

**Part i:**
$y'=6x^2-18x+12$ | M1 | condone one error

$=12$ | M1 | subst of $x=3$ in their $y'$

$y=7$ when $x=3$ | B1 |

tgt is $y-7=12(x-3)$ | M1 | f.t. their $y$ and $y'$

verifying $(-1,-41)$ on tgt | A1 | or B2 for showing line joining $(3,7)$ and $(-1,-41)$ has gradient 12 | 5

**Part ii:**
$y'=0$ s.o.i. | M1 | Their $y'$

quadratic with 3 terms | M1 | Any valid attempt at solution

$x=1$ or $2$ | A1 | or A1 for $(1,3)$ and A1 for $(2,2)$ marking to benefit of candidate

$y=3$ or $2$ | A1 | | 4

**Part iii:**
cubic curve correct orientation touching $x$-axis only at $(0.2,0)$ | G1 |

max and min correct | G1 | f.

curve crossing $y$-axis only at $-2$ | G1 | | 3

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4 (i) Differentiate $x ^ { 3 } - 3 x ^ { 2 } - 9 x$. Hence find the $x$-coordinates of the stationary points on the curve $y = x ^ { 3 } - 3 x ^ { 2 } - 9 x$, showing which is the maximum and which the minimum.\\
(ii) Find, in exact form, the coordinates of the points at which the curve crosses the $x$-axis.\\
(iii) Sketch the curve.

\hfill \mbox{\textit{OCR MEI C2  Q4 [11]}}