CAIE P2 2002 June — Question 6 10 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2002
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIndefinite & Definite Integrals
TypeTrapezium rule estimation
DifficultyModerate -0.3 This is a multi-part question with standard techniques: part (a)(i) is routine integration of cos 2x, part (a)(ii) requires the standard identity cos 2x = 1 - 2sin²x, part (b)(i) is straightforward trapezium rule application with 2 intervals, and part (b)(ii) requires recognizing that sec x is convex. All components are textbook exercises requiring recall and direct application rather than problem-solving, making it slightly easier than average.
Spec1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.08c Integrate e^(kx), 1/x, sin(kx), cos(kx)1.09f Trapezium rule: numerical integration

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    1. Show that \(\int _ { 0 } ^ { \frac { 1 } { 4 } \pi } \cos 2 x \mathrm {~d} x = \frac { 1 } { 2 }\).
    2. By using an appropriate trigonometrical identity, find the exact value of \(\int _ { 0 } ^ { \frac { 1 } { 4 } \pi } \sin ^ { 2 } x \mathrm {~d} x\).
    1. Use the trapezium rule with 2 intervals to estimate the value of \(\int _ { 0 } ^ { \frac { 1 } { 4 } \pi } \sec x d x\), giving your answer correct to 2 significant figures.
    2. Determine, by sketching the appropriate part of the graph of \(y = \sec x\), whether the trapezium rule gives an under-estimate or an over-estimate of the true value.

AnswerMarks Guidance
(a) (i) State indefinite integral \(k \sin 2x\) and use limitsM1
Obtain given answer correctlyA1 2
(ii) Use double-angle formula to convert integrand to the form \(a + b\cos 2x\), where \(ab \neq 0\)M1*
Integrate and use limits (both terms)M1(dep*)
Obtain answer \(\frac{1}{4}(x - 2)\), or equivalentA1 3
(b) (i) Show or imply correct ordinates \(1, 1.08239..., \sqrt{2}(1.41421...)\)B1
Use correct formula, or equivalent, with \(h = \pi/8\) and three ordinatesM1
Obtain correct answer \(0.90\) with no errors seenA1 3
(ii) Make a correct relevant sketch of \(y = \sec x\)B1*
State that the rule gives an over-estimateB1(dep*) 2
**(a) (i)** State indefinite integral $k \sin 2x$ and use limits | M1 |

Obtain given answer correctly | A1 | 2

**(ii)** Use double-angle formula to convert integrand to the form $a + b\cos 2x$, where $ab \neq 0$ | M1* |

Integrate and use limits (both terms) | M1(dep*) |

Obtain answer $\frac{1}{4}(x - 2)$, or equivalent | A1 | 3

**(b) (i)** Show or imply correct ordinates $1, 1.08239..., \sqrt{2}(1.41421...)$ | B1 |

Use correct formula, or equivalent, with $h = \pi/8$ and three ordinates | M1 |

Obtain correct answer $0.90$ with no errors seen | A1 | 3

**(ii)** Make a correct relevant sketch of $y = \sec x$ | B1* |

State that the rule gives an over-estimate | B1(dep*) | 2

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\begin{enumerate}[label=(\alph*)]
\item \begin{enumerate}[label=(\roman*)]
\item Show that $\int _ { 0 } ^ { \frac { 1 } { 4 } \pi } \cos 2 x \mathrm {~d} x = \frac { 1 } { 2 }$.
\item By using an appropriate trigonometrical identity, find the exact value of $\int _ { 0 } ^ { \frac { 1 } { 4 } \pi } \sin ^ { 2 } x \mathrm {~d} x$.
\end{enumerate}\item \begin{enumerate}[label=(\roman*)]
\item Use the trapezium rule with 2 intervals to estimate the value of $\int _ { 0 } ^ { \frac { 1 } { 4 } \pi } \sec x d x$, giving your answer correct to 2 significant figures.
\item Determine, by sketching the appropriate part of the graph of $y = \sec x$, whether the trapezium rule gives an under-estimate or an over-estimate of the true value.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{CAIE P2 2002 Q6 [10]}}