CAIE P2 2002 June — Question 4 8 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2002
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHarmonic Form
TypeExpress and solve equation
DifficultyModerate -0.3 This is a standard harmonic form question requiring routine application of the R cos(θ - α) formula, solving a trigonometric equation, and identifying a maximum from the harmonic form. All three parts follow textbook procedures with no novel problem-solving required, making it slightly easier than average for A-level.
Spec1.05n Harmonic form: a sin(x)+b cos(x) = R sin(x+alpha) etc1.05o Trigonometric equations: solve in given intervals

4
  1. Express \(3 \cos \theta + 2 \sin \theta\) in the form \(R \cos ( \theta - \alpha )\), where \(R > 0\) and \(0 ^ { \circ } < \alpha < 90 ^ { \circ }\), stating the exact value of \(R\) and giving the value of \(\alpha\) correct to 1 decimal place.
  2. Solve the equation $$3 \cos \theta + 2 \sin \theta = 3.5$$ giving all solutions in the interval \(0 ^ { \circ } \leqslant \theta \leqslant 180 ^ { \circ }\).
  3. The graph of \(y = 3 \cos \theta + 2 \sin \theta\), for \(0 ^ { \circ } \leqslant \theta \leqslant 180 ^ { \circ }\), has one stationary point. State the coordinates of this point. \includegraphics[max width=\textwidth, alt={}, center]{9b103197-7ba0-427a-b983-34edb51b6cca-3_421_823_299_662} The diagram shows the curve \(y = 2 x \mathrm { e } ^ { - x }\) and its maximum point \(P\). Each of the two points \(Q\) and \(R\) on the curve has \(y\)-coordinate equal to \(\frac { 1 } { 2 }\).

AnswerMarks Guidance
(i) State answer \(R = \sqrt{13}\)B1
Use trig formula to find \(\alpha\)M1
Obtain answer \(\alpha = 33.7°\)A1 3
(ii) Carry out, or indicate need for, evaluation of \(\cos^{-1}(3.5/\sqrt{13})\) (\(= 13.9°\))M1
Obtain answer \(47.6°\)A1
Carry out correct method for second answerM1
Obtain second answer \(19.8°\)A1 4
(iii) State coordinates \((33.7, \sqrt{13})\), or equivalentA1 1
**(i)** State answer $R = \sqrt{13}$ | B1 |

Use trig formula to find $\alpha$ | M1 |

Obtain answer $\alpha = 33.7°$ | A1 | 3

**(ii)** Carry out, or indicate need for, evaluation of $\cos^{-1}(3.5/\sqrt{13})$ ($= 13.9°$) | M1 |

Obtain answer $47.6°$ | A1 |

Carry out correct method for second answer | M1 |

Obtain second answer $19.8°$ | A1 | 4

**(iii)** State coordinates $(33.7, \sqrt{13})$, or equivalent | A1 | 1

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4 (i) Express $3 \cos \theta + 2 \sin \theta$ in the form $R \cos ( \theta - \alpha )$, where $R > 0$ and $0 ^ { \circ } < \alpha < 90 ^ { \circ }$, stating the exact value of $R$ and giving the value of $\alpha$ correct to 1 decimal place.\\
(ii) Solve the equation

$$3 \cos \theta + 2 \sin \theta = 3.5$$

giving all solutions in the interval $0 ^ { \circ } \leqslant \theta \leqslant 180 ^ { \circ }$.\\
(iii) The graph of $y = 3 \cos \theta + 2 \sin \theta$, for $0 ^ { \circ } \leqslant \theta \leqslant 180 ^ { \circ }$, has one stationary point. State the coordinates of this point.\\
\includegraphics[max width=\textwidth, alt={}, center]{9b103197-7ba0-427a-b983-34edb51b6cca-3_421_823_299_662}

The diagram shows the curve $y = 2 x \mathrm { e } ^ { - x }$ and its maximum point $P$. Each of the two points $Q$ and $R$ on the curve has $y$-coordinate equal to $\frac { 1 } { 2 }$.\\

\hfill \mbox{\textit{CAIE P2 2002 Q4 [8]}}