| Exam Board | OCR MEI |
|---|---|
| Module | C1 (Core Mathematics 1) |
| Marks | 13 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Curve Sketching |
| Type | Vertical translation of cubic with factorisation |
| Difficulty | Moderate -0.8 This is a structured multi-part question with clear signposting through standard C1 techniques: expanding brackets, substitution, factor theorem, and simple translation. All steps are routine with no problem-solving insight required—easier than average for A-level. |
| Spec | 1.02j Manipulate polynomials: expanding, factorising, division, factor theorem1.02n Sketch curves: simple equations including polynomials1.02w Graph transformations: simple transformations of f(x) |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| Sketch of cubic correct way up and with two turning points, crossing \(x\)-axis in 3 distinct points | B1 | 0 if stops at \(x\)-axis; condone not crossing \(y\)-axis; no section to be ruled; no curving back; condone slight 'flicking out' at ends; condone some doubling |
| Crossing \(x\)-axis at \(1\), \(2.5\) and \(4\) | B1 | Intersections labelled on graph or shown nearby; mark intent for intersections with both axes; allow \(2.5\) indicated by graph crossing halfway between their marked \(2\) and \(3\) on scale |
| Crossing \(y\)-axis at \(-20\) | B1 | Or \(x=0\), \(y=-20\) seen in this part if consistent with graph drawn; allow if no graph, but eg B0 for graph with intersection on \(+\)ve \(y\)-axis or nowhere near their indicated \(-20\) |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| Correct expansion of two brackets | M1 | Or M2 for all 3 brackets multiplied at once, showing all 8 terms (M1 if error in one term): \(2x^3-8x^2-2x^2-5x^2+8x+ x+20x-20\); eg M1 for \((2x-5)(x^2-5x+4)\); condone missing brackets if intent clear/used correctly |
| Correct interim step(s) multiplying out linear and quadratic factors before given answer | M1 | |
| Or showing that \(1\), \(2.5\) and \(4\) all satisfy \(f(x)=0\) for cubic in \(2x^3\ldots\) form | M1 | Or M1 for dividing \(2x^3\ldots\) form by one of the linear factors and M1 for factorising the resultant quadratic factor |
| Comparing coefficients of eg \(x^3\) in the two forms | M1 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| \(250-375+165-40\) isw | B1 | Or showing that \(x-5\) is a factor by eg division and then stating that \(x=5\) is root or that \(g(5)=0\); '\(2\times125+15\times25+33\times5-40\)' is not sufficient; or \([g(5)=]\ f(5)-20=5\times4\times1-20\ [=0]\) |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| \((x-5)\) seen or used as linear factor | M1 | May be in attempt at division; allow if seen in (ii)(A) |
| Division by \((x-5)\) as far as \(2x^3-10x^2\) seen in working | M1 | Or inspection/equating coefficients with two terms correct eg \((2x^2\ldots+8)\); for division: condone signs of \(2x^3-10x^2\) changed for subtraction, or subtraction sign in front of first term |
| \(2x^2-5x+8\) obtained isw | A1 | Eg may be seen in grid; condone \(g(x)\) not expressed as product |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| \(b^2-4ac\) used on their quadratic factor | M1 | May be in formula |
| \((-5)^2-4\times2\times8\) oe and negative [or \(-39\)] so no [real] root [may say only one [real] root, thinking of \(x=5\)] | A1 | [Or allow 2 marks for complete correct attempt at completing the square and conclusion, or using calculus to show min value is above \(x\)-axis and comment re curve all above \(x\)-axis]; no ft for A mark from wrong quadratic factor; condone error in working out \(-39\) if correct unsimplified expression seen and neg result obtained; \(-5^2-4\times2\times8\) evaluated correctly with comment is eligible for A1, otherwise bod for the M1 only |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| Translation | B1 | NB 'Moves' not sufficient for this first mark |
| \(\begin{pmatrix} 0 \\ -20 \end{pmatrix}\) | B1 | Or 20 down; B0 for second mark if choice of one wrong, one right description |
## Question 4:
### Part (i)(A):
| Answer | Mark | Guidance |
|--------|------|----------|
| Sketch of cubic correct way up and with two turning points, crossing $x$-axis in 3 distinct points | B1 | **0** if stops at $x$-axis; condone not crossing $y$-axis; no section to be ruled; no curving back; condone slight 'flicking out' at ends; condone some doubling |
| Crossing $x$-axis at $1$, $2.5$ and $4$ | B1 | Intersections labelled on graph or shown nearby; mark intent for intersections with both axes; allow $2.5$ indicated by graph crossing halfway between their marked $2$ and $3$ on scale |
| Crossing $y$-axis at $-20$ | B1 | Or $x=0$, $y=-20$ seen in this part if consistent with graph drawn; allow if no graph, but eg **B0** for graph with intersection on $+$ve $y$-axis or nowhere near their indicated $-20$ |
### Part (i)(B):
| Answer | Mark | Guidance |
|--------|------|----------|
| Correct expansion of two brackets | M1 | Or **M2** for all 3 brackets multiplied at once, showing all 8 terms (**M1** if error in one term): $2x^3-8x^2-2x^2-5x^2+8x+ x+20x-20$; eg **M1** for $(2x-5)(x^2-5x+4)$; condone missing brackets if intent clear/used correctly |
| Correct interim step(s) multiplying out linear and quadratic factors before given answer | M1 | |
| **Or** showing that $1$, $2.5$ and $4$ all satisfy $f(x)=0$ for cubic in $2x^3\ldots$ form | M1 | Or **M1** for dividing $2x^3\ldots$ form by one of the linear factors and **M1** for factorising the resultant quadratic factor |
| Comparing coefficients of eg $x^3$ in the two forms | M1 | |
### Part (ii)(A):
| Answer | Mark | Guidance |
|--------|------|----------|
| $250-375+165-40$ isw | B1 | Or showing that $x-5$ is a factor by eg division and then stating that $x=5$ is root or that $g(5)=0$; '$2\times125+15\times25+33\times5-40$' is not sufficient; or $[g(5)=]\ f(5)-20=5\times4\times1-20\ [=0]$ |
### Part (ii)(B):
| Answer | Mark | Guidance |
|--------|------|----------|
| $(x-5)$ seen or used as linear factor | M1 | May be in attempt at division; allow if seen in (ii)(A) |
| Division by $(x-5)$ as far as $2x^3-10x^2$ seen in working | M1 | Or inspection/equating coefficients with two terms correct eg $(2x^2\ldots+8)$; for division: condone signs of $2x^3-10x^2$ changed for subtraction, or subtraction sign in front of first term |
| $2x^2-5x+8$ obtained isw | A1 | Eg may be seen in grid; condone $g(x)$ not expressed as product |
### Part (ii)(C):
| Answer | Mark | Guidance |
|--------|------|----------|
| $b^2-4ac$ used on their quadratic factor | M1 | May be in formula |
| $(-5)^2-4\times2\times8$ oe and negative [or $-39$] so no [real] root [may say only one [real] root, thinking of $x=5$] | A1 | [Or allow **2** marks for complete correct attempt at completing the square and conclusion, or using calculus to show min value is above $x$-axis and comment re curve all above $x$-axis]; no ft for A mark from wrong quadratic factor; condone error in working out $-39$ if correct unsimplified expression seen and neg result obtained; $-5^2-4\times2\times8$ evaluated correctly with comment is eligible for **A1**, otherwise bod for the **M1** only |
### Part (iii):
| Answer | Mark | Guidance |
|--------|------|----------|
| Translation | B1 | NB 'Moves' not sufficient for this first mark |
| $\begin{pmatrix} 0 \\ -20 \end{pmatrix}$ | B1 | Or 20 down; **B0** for second mark if choice of one wrong, one right description |
4
\begin{enumerate}[label=(\roman*)]
\item You are given that $\mathrm { f } ( x ) = ( 2 x - 5 ) ( x - 1 ) ( x - 4 )$.\\
(A) Sketch the graph of $y = \mathrm { f } ( x )$.\\
(B) Show that $\mathrm { f } ( x ) = 2 x ^ { 3 } - 15 x ^ { 2 } + 33 x - 20$.
\item You are given that $\mathrm { g } ( x ) = 2 x ^ { 3 } - 15 x ^ { 2 } + 33 x - 40$.\\
(A) Show that $\mathrm { g } ( 5 ) = 0$.\\
(B) Express $\mathrm { g } ( x )$ as the product of a linear and quadratic factor.\\
(C) Hence show that the equation $\mathrm { g } ( x ) = 0$ has only one real root.
\item Describe fully the transformation that maps $y = \mathrm { f } ( x )$ onto $y = \mathrm { g } ( x )$.
\end{enumerate}
\hfill \mbox{\textit{OCR MEI C1 Q4 [13]}}