| Exam Board | OCR MEI |
|---|---|
| Module | C1 (Core Mathematics 1) |
| Marks | 12 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Curve Sketching |
| Type | Vertical translation of cubic with factorisation |
| Difficulty | Moderate -0.8 This is a straightforward C1 question involving routine algebraic expansion, basic transformations (vertical translation), and factor theorem application. All parts follow standard procedures with no problem-solving insight required—easier than average for A-level. |
| Spec | 1.02j Manipulate polynomials: expanding, factorising, division, factor theorem1.02n Sketch curves: simple equations including polynomials1.02w Graph transformations: simple transformations of f(x) |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| Graph of cubic correct way up | B1 | B0 if stops at \(x\)-axis; must not have any ruled sections; no curving back; condone slight 'flicking out' at ends but not approaching a turning point; allow max on \(y\)-axis or in 1st or 2nd quadrants |
| Crossing \(x\)-axis at \(-3\), \(2\) and \(5\) | B1 | On graph or nearby; may be in coordinate form; mark intent for intersections with both axes; allow if no graph but marked on \(x\)-axis; condone intercepts for \(x\) and/or \(y\) given as reversed coordinates |
| Crossing \(y\)-axis at \(30\) | B1 | Or \(x=0\), \(y=30\) seen if consistent with graph drawn; allow if no graph, but eg B0 for graph with intersection on \(y\)-axis nowhere near their indicated \(30\) |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| Correct expansion of two of the linear factors | M1 | May be 3 or 4 terms; condone lack of brackets if correct expansions as if they were there |
| Correct expansion and completion to given answer, \(x^3 - 4x^2 - 11x + 30\) | A1 | Must be working for this step before given answer; or for direct expansion of all three factors, allow M1 for \(x^3+3x^2-2x^2-5x^2-6x-15x+10x+30\), condoning an error in one term, and A1 if no error for completion by stating given answer |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| Translation | B1 | 0 for shift or move etc without stating translation; 0 if eg stretch also mentioned |
| \(\begin{pmatrix} 0 \\ -36 \end{pmatrix}\) | B1 | Or 36 down, or \(-36\) in \(y\) direction oe; if conflict eg between '\(-36\) in \(y\) direction' and wrong vector, award B0; 0 for '\(-36\) down' |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Mark | Guidance |
| \(-1-4+11-6=0\) | B1 | Or B1 for correct division by \((x+1)\) or for the quadratic factor found by inspection, and the conclusion that no remainder means \(g(-1)=0\); NB examiners must use annotation in this part |
| Attempt at division by \((x+1)\) as far as \(x^3+x^2\) in working | M1 | Or inspection with at least two terms of three-term quadratic factor correct; or finding \(f(6)=0\); M0 for trials of factors to give cubic unless correct answer found with clear correct working |
| Correctly obtaining \(x^2-5x-6\) | A1 | Or \((x-6)\) found as factor |
| Factorising the correct quadratic factor \(x^2-5x-6\) that has been correctly obtained | M1 | For factors giving two terms of quadratic correct or for factors ft one error in quadratic formula or completing the square; M0 for formula etc without factors found; allow for \((x-6)\) and \((x+1)\) given as factors |
| \((x-6)(x+1)^2\) oe isw | A1 | Condone inclusion of '\(=0\)'; isw roots found, even if stated as factors; just the answer \((x-6)(x+1)^2\) oe gets last 4 marks |
## Question 3:
### Part (i):
| Answer | Mark | Guidance |
|--------|------|----------|
| Graph of cubic correct way up | B1 | **B0** if stops at $x$-axis; must not have any ruled sections; no curving back; condone slight 'flicking out' at ends but not approaching a turning point; allow max on $y$-axis or in 1st or 2nd quadrants |
| Crossing $x$-axis at $-3$, $2$ and $5$ | B1 | On graph or nearby; may be in coordinate form; mark intent for intersections with both axes; allow if no graph but marked on $x$-axis; condone intercepts for $x$ and/or $y$ given as reversed coordinates |
| Crossing $y$-axis at $30$ | B1 | Or $x=0$, $y=30$ seen if consistent with graph drawn; allow if no graph, but eg B0 for graph with intersection on $y$-axis nowhere near their indicated $30$ |
**[3]**
### Part (ii):
| Answer | Mark | Guidance |
|--------|------|----------|
| Correct expansion of two of the linear factors | M1 | May be 3 or 4 terms; condone lack of brackets if correct expansions as if they were there |
| Correct expansion and completion to given answer, $x^3 - 4x^2 - 11x + 30$ | A1 | Must be working for this step before given answer; or for direct expansion of all three factors, allow M1 for $x^3+3x^2-2x^2-5x^2-6x-15x+10x+30$, condoning an error in one term, and A1 if no error for completion by stating given answer |
**[2]**
### Part (iii):
| Answer | Mark | Guidance |
|--------|------|----------|
| Translation | B1 | 0 for shift or move etc without stating translation; 0 if eg stretch also mentioned |
| $\begin{pmatrix} 0 \\ -36 \end{pmatrix}$ | B1 | Or 36 down, or $-36$ in $y$ direction oe; if conflict eg between '$-36$ in $y$ direction' and wrong vector, award B0; 0 for '$-36$ down' |
**[2]**
### Part (iv):
| Answer | Mark | Guidance |
|--------|------|----------|
| $-1-4+11-6=0$ | B1 | Or **B1** for correct division by $(x+1)$ or for the quadratic factor found by inspection, **and** the conclusion that no remainder means $g(-1)=0$; NB examiners must use annotation in this part |
| Attempt at division by $(x+1)$ as far as $x^3+x^2$ in working | M1 | Or inspection with at least two terms of three-term quadratic factor correct; or finding $f(6)=0$; M0 for trials of factors to give cubic unless correct answer found with clear correct working |
| Correctly obtaining $x^2-5x-6$ | A1 | Or $(x-6)$ found as factor |
| Factorising the correct quadratic factor $x^2-5x-6$ that has been correctly obtained | M1 | For factors giving two terms of quadratic correct or for factors ft one error in quadratic formula or completing the square; **M0** for formula etc without factors found; allow for $(x-6)$ and $(x+1)$ given as factors |
| $(x-6)(x+1)^2$ oe isw | A1 | Condone inclusion of '$=0$'; isw roots found, even if stated as factors; just the answer $(x-6)(x+1)^2$ oe gets last 4 marks |
**[5]**
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3 You are given that $\mathrm { f } ( x ) = ( x + 3 ) ( x - 2 ) ( x - 5 )$.\\
(i) Sketch the curve $y = \mathrm { f } ( x )$.\\
(ii) Show that $\mathrm { f } ( x )$ may be written as $x ^ { 3 } - 4 x ^ { 2 } - 11 x + 30$.\\
(iii) Describe fully the transformation that maps the graph of $y = \mathrm { f } ( x )$ onto the graph of $y = \mathrm { g } ( x )$, where $\mathrm { g } ( x ) = x ^ { 3 } - 4 x ^ { 2 } - 11 x - 6$.\\
(iv) Show that $\mathrm { g } ( - 1 ) = 0$. Hence factorise $\mathrm { g } ( x )$ completely.
\hfill \mbox{\textit{OCR MEI C1 Q3 [12]}}