CAIE P2 2021 November — Question 7 9 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2021
SessionNovember
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAddition & Double Angle Formulae
TypeDerive triple angle then evaluate integral
DifficultyStandard +0.3 This is a structured multi-part question that guides students through deriving a triple angle formula then applying it. Part (a) is routine expansion using addition formulae, part (b) is direct substitution requiring recognition that the expression equals cos(5π/6)/2, and part (c) requires reversing the identity to integrate. While it spans multiple techniques, each step is straightforward with clear signposting, making it slightly easier than average.
Spec1.05l Double angle formulae: and compound angle formulae1.05p Proof involving trig: functions and identities1.08c Integrate e^(kx), 1/x, sin(kx), cos(kx)

7
  1. By first expanding \(\cos ( 2 \theta + \theta )\), show that \(\cos 3 \theta \equiv 4 \cos ^ { 3 } \theta - 3 \cos \theta\).
  2. Find the exact value of \(2 \cos ^ { 3 } \left( \frac { 5 } { 18 } \pi \right) - \frac { 3 } { 2 } \cos \left( \frac { 5 } { 18 } \pi \right)\).
  3. Find \(\int \left( 12 \cos ^ { 3 } x - 4 \cos ^ { 3 } 3 x \right) \mathrm { d } x\).
    If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.

Question 7(a):
AnswerMarks Guidance
AnswerMark Guidance
State \(\cos 2\theta\cos\theta - \sin 2\theta\sin\theta\)B1
Attempt correct relevant identities to express in terms of \(\cos\theta\) onlyM1 M0 if moving terms from side to side
Confirm \(4\cos^3\theta - 3\cos\theta\) with sufficient detailA1 AG
3
Question 7(b):
AnswerMarks Guidance
AnswerMark Guidance
Use identity with \(\theta = \frac{5}{18}\pi\)M1
Obtain \(\frac{1}{2}\cos\frac{5}{6}\pi\) and hence \(-\frac{1}{4}\sqrt{3}\)A1
2
Question 7(c):
AnswerMarks Guidance
AnswerMark Guidance
Express integrand in form \(k_1(\cos 3x + 3\cos x) + k_2(\cos 9x + 3\cos 3x)\)M1
Obtain correct integrand \(9\cos x - \cos 9x\)A1 OE (allow unsimplified)
Integrate to obtain form \(k_3\sin x + k_4\sin 9x\)M1
Obtain correct \(9\sin x - \frac{1}{9}\sin 9x\)A1 Now simplified; condone missing \(\ldots + c\)
4
## Question 7(a):

| Answer | Mark | Guidance |
|--------|------|----------|
| State $\cos 2\theta\cos\theta - \sin 2\theta\sin\theta$ | B1 | |
| Attempt correct relevant identities to express in terms of $\cos\theta$ only | M1 | M0 if moving terms from side to side |
| Confirm $4\cos^3\theta - 3\cos\theta$ with sufficient detail | A1 | AG |
| | **3** | |

---

## Question 7(b):

| Answer | Mark | Guidance |
|--------|------|----------|
| Use identity with $\theta = \frac{5}{18}\pi$ | M1 | |
| Obtain $\frac{1}{2}\cos\frac{5}{6}\pi$ and hence $-\frac{1}{4}\sqrt{3}$ | A1 | |
| | **2** | |

---

## Question 7(c):

| Answer | Mark | Guidance |
|--------|------|----------|
| Express integrand in form $k_1(\cos 3x + 3\cos x) + k_2(\cos 9x + 3\cos 3x)$ | M1 | |
| Obtain correct integrand $9\cos x - \cos 9x$ | A1 | OE (allow unsimplified) |
| Integrate to obtain form $k_3\sin x + k_4\sin 9x$ | M1 | |
| Obtain correct $9\sin x - \frac{1}{9}\sin 9x$ | A1 | Now simplified; condone missing $\ldots + c$ |
| | **4** | |
7
\begin{enumerate}[label=(\alph*)]
\item By first expanding $\cos ( 2 \theta + \theta )$, show that $\cos 3 \theta \equiv 4 \cos ^ { 3 } \theta - 3 \cos \theta$.
\item Find the exact value of $2 \cos ^ { 3 } \left( \frac { 5 } { 18 } \pi \right) - \frac { 3 } { 2 } \cos \left( \frac { 5 } { 18 } \pi \right)$.
\item Find $\int \left( 12 \cos ^ { 3 } x - 4 \cos ^ { 3 } 3 x \right) \mathrm { d } x$.\\

If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.
\end{enumerate}

\hfill \mbox{\textit{CAIE P2 2021 Q7 [9]}}