CAIE P2 2021 November — Question 2 6 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2021
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicModulus function
TypeSketch modulus of linear and non-modulus linear, find intersection
DifficultyModerate -0.8 This is a straightforward modulus question requiring a standard sketch of two simple functions, solving a basic equation by cases (|x-3| = 3x), and reading off an inequality from the graph. All techniques are routine for P2 level with no conceptual challenges or novel problem-solving required.
Spec1.02g Inequalities: linear and quadratic in single variable1.02s Modulus graphs: sketch graph of |ax+b|

2
  1. Sketch, on the same diagram, the graphs of \(y = 3 x\) and \(y = | x - 3 |\).
  2. Find the coordinates of the point where the two graphs intersect.
  3. Deduce the solution of the inequality \(3 x < | x - 3 |\).

Question 2(a):
AnswerMarks Guidance
AnswerMarks Guidance
Draw V-shaped graph with vertex on positive \(x\)-axisB1 Must be straight lines.
Draw straight line through origin with positive gradient greater than gradient of first graph, together with a V shaped graphB1 Must have the first B1.
Question 2(b):
AnswerMarks Guidance
AnswerMarks Guidance
Solve linear equation with signs of \(3x\) and \(x\) different or solve non-modulus equation \((3x)^2 = (x-3)^2\)M1
Obtain \(x = \frac{3}{4}\)A1
Obtain \(y = \frac{9}{4}\)A1 And no other point.
Question 2(c):
AnswerMarks Guidance
AnswerMarks Guidance
State \(x < \frac{3}{4}\)B1 FT Following *their* (single) \(x\)-coordinate from part (b).
## Question 2(a):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Draw V-shaped graph with vertex on positive $x$-axis | **B1** | Must be straight lines. |
| Draw straight line through origin with positive gradient greater than gradient of first graph, together with a V shaped graph | **B1** | Must have the first **B1**. |

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## Question 2(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Solve linear equation with signs of $3x$ and $x$ different or solve non-modulus equation $(3x)^2 = (x-3)^2$ | **M1** | |
| Obtain $x = \frac{3}{4}$ | **A1** | |
| Obtain $y = \frac{9}{4}$ | **A1** | And no other point. |

---

## Question 2(c):

| Answer | Marks | Guidance |
|--------|-------|----------|
| State $x < \frac{3}{4}$ | **B1 FT** | Following *their* (single) $x$-coordinate from part **(b)**. |
2
\begin{enumerate}[label=(\alph*)]
\item Sketch, on the same diagram, the graphs of $y = 3 x$ and $y = | x - 3 |$.
\item Find the coordinates of the point where the two graphs intersect.
\item Deduce the solution of the inequality $3 x < | x - 3 |$.
\end{enumerate}

\hfill \mbox{\textit{CAIE P2 2021 Q2 [6]}}