Edexcel FP2 2003 June — Question 5 6 marks

Exam BoardEdexcel
ModuleFP2 (Further Pure Mathematics 2)
Year2003
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicInequalities
TypeRational inequality algebraically
DifficultyStandard +0.3 This is a standard rational inequality requiring algebraic manipulation (bringing to common denominator, finding critical points, sign analysis). While it's Further Maths, the technique is routine and methodical with no novel insight required—slightly easier than average overall but typical for FP2.
Spec1.02g Inequalities: linear and quadratic in single variable

5. Solve the inequality \(\frac { 1 } { 2 x + 1 } > \frac { x } { 3 x - 2 }\).

AnswerMarks
Identifying as critical values \(-\frac{1}{2}, \frac{2}{3}\)B1, B1
Establishing there are no further critical values
Obtaining \(2x^2 - 2x - 2\) or equivalentM1
A1
\(\Delta = 4 - 16 < 0\)
Using exactly two critical values to obtain inequalitiesM1
\(-\frac{1}{2} < x < \frac{2}{3}\)A1
(6 marks)
Identifying \(x = -\frac{1}{2}\) and \(x = \frac{2}{3}\) as vertical asymptotesB1; B1
Two rectangular hyperbolae oriented correctly with respect to asymptotes in the correct half-planesM1
Two correctly drawn curves with no intersectionsA1
As aboveM1, A1
Identifying as critical values $-\frac{1}{2}, \frac{2}{3}$ | B1, B1 |

Establishing there are no further critical values | |

Obtaining $2x^2 - 2x - 2$ or equivalent | M1 |
| A1 |

$\Delta = 4 - 16 < 0$ | |

Using exactly two critical values to obtain inequalities | M1 |

$-\frac{1}{2} < x < \frac{2}{3}$ | A1 |

| | (6 marks) |

Identifying $x = -\frac{1}{2}$ and $x = \frac{2}{3}$ as vertical asymptotes | B1; B1 |

Two rectangular hyperbolae oriented correctly with respect to asymptotes in the correct half-planes | M1 |

Two correctly drawn curves with no intersections | A1 |

As above | M1, A1 |

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5. Solve the inequality $\frac { 1 } { 2 x + 1 } > \frac { x } { 3 x - 2 }$.\\

\hfill \mbox{\textit{Edexcel FP2 2003 Q5 [6]}}