Edexcel FP2 2003 June — Question 13 11 marks

Exam BoardEdexcel
ModuleFP2 (Further Pure Mathematics 2)
Year2003
SessionJune
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComplex Numbers Argand & Loci
TypeGeometric relationships on Argand diagram
DifficultyStandard +0.3 This is a straightforward Further Maths question testing basic complex number operations (squaring, reciprocal, modulus) and a simple similarity proof. All parts are routine applications of standard techniques with no novel insight required, though the similarity proof adds slight challenge beyond pure computation.
Spec4.02a Complex numbers: real/imaginary parts, modulus, argument4.02b Express complex numbers: cartesian and modulus-argument forms4.02c Complex notation: z, z*, Re(z), Im(z), |z|, arg(z)

13. Given that \(z = 3 - 3 i\) express, in the form \(a + i b\), where \(a\) and \(b\) are real numbers,
  1. \(z ^ { 2 }\),
    (2)
  2. \(\frac { 1 } { z }\).
    (2)
  3. Find the exact value of each of \(| z | , \left| z ^ { 2 } \right|\) and \(\left| \frac { 1 } { z } \right|\).
    (2) The complex numbers \(z , z ^ { 2 }\) and \(\frac { 1 } { z }\) are represented by the points \(A , B\) and \(C\) respectively on an Argand diagram. The real number 1 is represented by the point \(D\), and \(O\) is the origin.
  4. Show the points \(A , B , C\) and \(D\) on an Argand diagram.
  5. Prove that \(\triangle O A B\) is similar to \(\triangle O C D\).

AnswerMarks Guidance
\(z^2 = (3 - 3i)(3 - 3i) = -18i\)M1 A1 (2)
(b) \(\frac{1}{z} = \frac{(3+3i)}{(3-3i)(3+3i)} = \frac{3+3i}{18} = \frac{1+i}{6}\)M1 A1 (2)
(c) \(z = \sqrt{(9+9)} = \sqrt{18} = 3\sqrt{2}\)
\(z = 18\)
\(\left\frac{1}{z}\right = \sqrt{\frac{1}{18}} = \frac{1}{3\sqrt{2}} = \frac{\sqrt{2}}{6}\)
(d) Two correctB1 (2)
Four correctB1
AnswerMarks Guidance
\(OB = 18, \quad OA = \frac{3\sqrt{2}}{\sqrt{2}/6} = 18\)M1 A1
\(\angle AOB = \angle COD = 45 \therefore\) similarB1 (3)
(11 marks)
$z^2 = (3 - 3i)(3 - 3i) = -18i$ | M1 A1 | (2) |

**(b)** $\frac{1}{z} = \frac{(3+3i)}{(3-3i)(3+3i)} = \frac{3+3i}{18} = \frac{1+i}{6}$ | M1 A1 | (2) |

**(c)** $|z| = \sqrt{(9+9)} = \sqrt{18} = 3\sqrt{2}$ | |

$|z| = 18$ | two correct | M1 |

$\left|\frac{1}{z}\right| = \sqrt{\frac{1}{18}} = \frac{1}{3\sqrt{2}} = \frac{\sqrt{2}}{6}$ | all three correct | A1 | (2) |

**(d)** Two correct | B1 | (2) |

Four correct | B1 |

| |

$OB = 18, \quad OA = \frac{3\sqrt{2}}{\sqrt{2}/6} = 18$ | M1 A1 |

$\angle AOB = \angle COD = 45 \therefore$ similar | B1 | (3) |

| | (11 marks) |

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13. Given that $z = 3 - 3 i$ express, in the form $a + i b$, where $a$ and $b$ are real numbers,
\begin{enumerate}[label=(\alph*)]
\item $z ^ { 2 }$,\\
(2)
\item $\frac { 1 } { z }$.\\
(2)
\item Find the exact value of each of $| z | , \left| z ^ { 2 } \right|$ and $\left| \frac { 1 } { z } \right|$.\\
(2)

The complex numbers $z , z ^ { 2 }$ and $\frac { 1 } { z }$ are represented by the points $A , B$ and $C$ respectively on an Argand diagram. The real number 1 is represented by the point $D$, and $O$ is the origin.
\item Show the points $A , B , C$ and $D$ on an Argand diagram.
\item Prove that $\triangle O A B$ is similar to $\triangle O C D$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel FP2 2003 Q13 [11]}}