Edexcel FP1 2010 June — Question 2 5 marks

Exam BoardEdexcel
ModuleFP1 (Further Pure Mathematics 1)
Year2010
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMatrices
TypeSingular matrix conditions
DifficultyModerate -0.8 This is a straightforward Further Maths question testing basic matrix concepts: computing a 2×2 inverse using the standard formula and finding when determinant equals zero. Both parts require only direct application of standard procedures with minimal algebraic manipulation (solving 2a² - 18 = 0). While it's Further Maths content, the techniques are routine and mechanical.
Spec4.03l Singular/non-singular matrices4.03n Inverse 2x2 matrix4.03o Inverse 3x3 matrix

2. \(\mathbf { M } = \left( \begin{array} { c c } 2 a & 3 \\ 6 & a \end{array} \right)\), where \(a\) is a real constant.
  1. Given that \(a = 2\), find \(\mathbf { M } ^ { - 1 }\).
  2. Find the values of \(a\) for which \(\mathbf { M }\) is singular.

AnswerMarks Guidance
(a) \(M = \begin{pmatrix} 4 & 3 \\ 6 & 2 \end{pmatrix}\)B1 Determinant must be \(-10\)
\(M^{-1} = \frac{1}{-10}\begin{pmatrix} 2 & -3 \\ -6 & 4 \end{pmatrix} = \begin{pmatrix} -0.2 & 0.3 \\ 0.6 & -0.4 \end{pmatrix}\)M1 A1 M1: for correct attempt at changing elements in major diagonal and changing signs in minor diagonal. Three or four of the numbers in the matrix should be correct – eg allow one slip. A1: for any form of correct answer, with correct determinant then isw.
(b) Setting \(\Delta = 0\) and using \(2a^2 \pm 18 = 0\) to obtain \(a = \pm 3\)M1, A1 cao (2 marks)
Guidance: Special case: \(a\) not replaced is B0M1A0
**(a)** $M = \begin{pmatrix} 4 & 3 \\ 6 & 2 \end{pmatrix}$ | **B1** | Determinant must be $-10$

$M^{-1} = \frac{1}{-10}\begin{pmatrix} 2 & -3 \\ -6 & 4 \end{pmatrix} = \begin{pmatrix} -0.2 & 0.3 \\ 0.6 & -0.4 \end{pmatrix}$ | **M1 A1** | M1: for correct attempt at changing elements in major diagonal and changing signs in minor diagonal. Three or four of the numbers in the matrix should be correct – eg allow one slip. A1: for any form of correct answer, with correct determinant then isw.

**(b)** Setting $\Delta = 0$ and using $2a^2 \pm 18 = 0$ to obtain $a = \pm 3$ | **M1, A1 cao** | (2 marks)

**Guidance:** Special case: $a$ not replaced is **B0M1A0**

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2. $\mathbf { M } = \left( \begin{array} { c c } 2 a & 3 \\ 6 & a \end{array} \right)$, where $a$ is a real constant.
\begin{enumerate}[label=(\alph*)]
\item Given that $a = 2$, find $\mathbf { M } ^ { - 1 }$.
\item Find the values of $a$ for which $\mathbf { M }$ is singular.
\end{enumerate}

\hfill \mbox{\textit{Edexcel FP1 2010 Q2 [5]}}