Edexcel FP1 2010 June — Question 6 9 marks

Exam BoardEdexcel
ModuleFP1 (Further Pure Mathematics 1)
Year2010
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLinear transformations
TypeCombined transformation matrix product
DifficultyModerate -0.8 This is a straightforward Further Maths question testing basic matrix operations: writing down standard transformation matrices from memory (parts a-b), multiplying two 2×2 matrices (parts c-d), and solving simultaneous equations by equating matrix entries (part e). All steps are routine with no problem-solving or insight required beyond direct application of learned procedures.
Spec4.03d Linear transformations 2D: reflection, rotation, enlargement, shear4.03e Successive transformations: matrix products

6. Write down the \(2 \times 2\) matrix that represents
  1. an enlargement with centre \(( 0,0 )\) and scale factor 8 ,
  2. a reflection in the \(x\)-axis. Hence, or otherwise,
  3. find the matrix \(\mathbf { T }\) that represents an enlargement with centre ( 0,0 ) and scale factor 8, followed by a reflection in the \(x\)-axis. $$\mathbf { A } = \left( \begin{array} { l l } 6 & 1 \\ 4 & 2 \end{array} \right) \text { and } \mathbf { B } = \left( \begin{array} { r r } k & 1 \\ c & - 6 \end{array} \right) , \text { where } k \text { and } c \text { are constants. }$$
  4. Find \(\mathbf { A B }\). Given that \(\mathbf { A B }\) represents the same transformation as \(\mathbf { T }\),
  5. find the value of \(k\) and the value of \(c\).

AnswerMarks Guidance
(a) \(\begin{pmatrix} 8 & 0 \\ 0 & 8 \end{pmatrix}\)B1 (1 mark)
(b) \(\begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix}\)B1 (1 mark)
(c) \(\mathbf{T} = \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix}\begin{pmatrix} 8 & 0 \\ 0 & 8 \end{pmatrix} = \begin{pmatrix} 8 & 0 \\ 0 & -8 \end{pmatrix}\)M1 A1 M1: Accept multiplication of their matrices either way round (this can be implied by correct answer). A1: cao
(d) \(\mathbf{AB} = \begin{pmatrix} 6 & 1 \\ 4 & 2 \end{pmatrix}\begin{pmatrix} k & 1 \\ c & -6 \end{pmatrix} = \begin{pmatrix} 6k + c & 0 \\ 4k + 2c & -8 \end{pmatrix}\)M1 A1 A1 M1: Correct matrix multiplication method implied by one or two correct terms in correct positions. A1: for three correct terms in correct positions. Second A1: for all four terms correct and simplified
(e) "\(6k + c = 8\)" and "\(4k + 2c = 0\)"M1, A1 Form equations and solve simultaneously
\(k = 2\) and \(c = -4\) (2 marks)
Total: 9 marks
Alternative method for (e): M1: \(\mathbf{AB} = \mathbf{T} \Rightarrow \mathbf{B} = \mathbf{A}^{-1}\mathbf{T}\) and compare elements to find \(k\) and \(c\). Then A1 as before.
Guidance:
(c) M1: Accept multiplication of their matrices either way round (this can be implied by correct answer). A1: cao
(d) M1: Correct matrix multiplication method implied by one or two correct terms in correct positions. A1: for three correct terms in correct positions. Second A1: for all four terms correct and simplified
(e) M1: follows their previous work but must give two equations from which \(k\) and \(c\) can be found and there must be attempt at solution getting to \(k = \) or \(c = \). A1: is cao (but not cso – may follow error in position of \(4k + 2c\) earlier).
**(a)** $\begin{pmatrix} 8 & 0 \\ 0 & 8 \end{pmatrix}$ | **B1** | (1 mark)

**(b)** $\begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix}$ | **B1** | (1 mark)

**(c)** $\mathbf{T} = \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix}\begin{pmatrix} 8 & 0 \\ 0 & 8 \end{pmatrix} = \begin{pmatrix} 8 & 0 \\ 0 & -8 \end{pmatrix}$ | **M1 A1** | M1: Accept multiplication of their matrices either way round (this can be implied by correct answer). A1: cao | (2 marks)

**(d)** $\mathbf{AB} = \begin{pmatrix} 6 & 1 \\ 4 & 2 \end{pmatrix}\begin{pmatrix} k & 1 \\ c & -6 \end{pmatrix} = \begin{pmatrix} 6k + c & 0 \\ 4k + 2c & -8 \end{pmatrix}$ | **M1 A1 A1** | M1: Correct matrix multiplication method implied by one or two correct terms in correct positions. A1: for three correct terms in correct positions. Second A1: for all four terms correct and simplified | (3 marks)

**(e)** "$6k + c = 8$" and "$4k + 2c = 0$" | **M1, A1** | Form equations and solve simultaneously | 

$k = 2$ and $c = -4$ | | (2 marks)

**Total: 9 marks**

**Alternative method for (e):** M1: $\mathbf{AB} = \mathbf{T} \Rightarrow \mathbf{B} = \mathbf{A}^{-1}\mathbf{T}$ and compare elements to find $k$ and $c$. Then A1 as before.

**Guidance:**

(c) M1: Accept multiplication of their matrices either way round (this can be implied by correct answer). A1: cao

(d) M1: Correct matrix multiplication method implied by one or two correct terms in correct positions. A1: for three correct terms in correct positions. Second A1: for all four terms correct and simplified

(e) M1: follows their previous work but must give two equations from which $k$ and $c$ can be found and there must be attempt at solution getting to $k = $ or $c = $. A1: is cao (but not cso – may follow error in position of $4k + 2c$ earlier).

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6. Write down the $2 \times 2$ matrix that represents
\begin{enumerate}[label=(\alph*)]
\item an enlargement with centre $( 0,0 )$ and scale factor 8 ,
\item a reflection in the $x$-axis.

Hence, or otherwise,
\item find the matrix $\mathbf { T }$ that represents an enlargement with centre ( 0,0 ) and scale factor 8, followed by a reflection in the $x$-axis.

$$\mathbf { A } = \left( \begin{array} { l l } 
6 & 1 \\
4 & 2
\end{array} \right) \text { and } \mathbf { B } = \left( \begin{array} { r r } 
k & 1 \\
c & - 6
\end{array} \right) , \text { where } k \text { and } c \text { are constants. }$$
\item Find $\mathbf { A B }$.

Given that $\mathbf { A B }$ represents the same transformation as $\mathbf { T }$,
\item find the value of $k$ and the value of $c$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel FP1 2010 Q6 [9]}}