Edexcel FP1 2010 June — Question 4 7 marks

Exam BoardEdexcel
ModuleFP1 (Further Pure Mathematics 1)
Year2010
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicRoots of polynomials
TypeFactor theorem and finding roots
DifficultyModerate -0.8 This is a straightforward Further Pure question requiring polynomial division to find coefficients, then solving a quadratic (which has complex roots). Part (c) is trivial using Vieta's formulas or summing the found roots. All steps are routine techniques with no problem-solving insight required, making it easier than average despite being FP1.
Spec1.02j Manipulate polynomials: expanding, factorising, division, factor theorem4.05a Roots and coefficients: symmetric functions

4. $$f ( x ) = x ^ { 3 } + x ^ { 2 } + 44 x + 150$$ Given that \(\mathrm { f } ( x ) = ( x + 3 ) \left( x ^ { 2 } + a x + b \right)\), where \(a\) and \(b\) are real constants,
  1. find the value of \(a\) and the value of \(b\).
  2. Find the three roots of \(\mathrm { f } ( x ) = 0\).
  3. Find the sum of the three roots of \(\mathrm { f } ( x ) = 0\).

AnswerMarks Guidance
(a) \(a = -2, b = 50\)B1, B1 (2 marks)
(b) \(-3\) is a rootB1
Solving 3-term quadratic: \(x = \frac{2 \pm \sqrt{4 - 200}}{2}\) or \((x-1)^2 - 1 + 50 = 0\)M1
\(= 1 + 7i, 1 - 7i\)A1, A1 ft A1: for a correct root (simplified as here) and A1 ft: for conjugate of first answer. Accept correct answers with no working here. If answers are written down as factors then isw. Must see roots for marks.
(c) \((-3) + (1 + 7i) + (1 - 7i) = -1\)B1 ft Requires the sum of two non-real conjugate roots and a real root resulting in a real number. Answers including \(x\) are B0
Total: 7 marks
**(a)** $a = -2, b = 50$ | **B1, B1** | (2 marks)

**(b)** $-3$ is a root | **B1** | 

Solving 3-term quadratic: $x = \frac{2 \pm \sqrt{4 - 200}}{2}$ or $(x-1)^2 - 1 + 50 = 0$ | **M1** |

$= 1 + 7i, 1 - 7i$ | **A1, A1 ft** | A1: for a correct root (simplified as here) and A1 ft: for conjugate of first answer. Accept correct answers with no working here. If answers are written down as factors then isw. Must see roots for marks.

**(c)** $(-3) + (1 + 7i) + (1 - 7i) = -1$ | **B1 ft** | Requires the sum of two non-real conjugate roots and a real root resulting in a real number. Answers including $x$ are **B0**

**Total: 7 marks**

---
4.

$$f ( x ) = x ^ { 3 } + x ^ { 2 } + 44 x + 150$$

Given that $\mathrm { f } ( x ) = ( x + 3 ) \left( x ^ { 2 } + a x + b \right)$, where $a$ and $b$ are real constants,
\begin{enumerate}[label=(\alph*)]
\item find the value of $a$ and the value of $b$.
\item Find the three roots of $\mathrm { f } ( x ) = 0$.
\item Find the sum of the three roots of $\mathrm { f } ( x ) = 0$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel FP1 2010 Q4 [7]}}