Edexcel F1 2023 January — Question 9 6 marks

Exam BoardEdexcel
ModuleF1 (Further Pure Mathematics 1)
Year2023
SessionJanuary
Marks6
PaperDownload PDF ↗
TopicProof by induction
TypeProve summation with logarithms
DifficultyChallenging +1.2 This is a Further Maths proof by induction involving logarithms and factorials. While the algebraic manipulation requires careful handling of log laws and factorial expressions, the inductive structure is standard. The key insight—recognizing that the product of odd numbers relates to factorials—is moderately challenging but within reach for Further Maths students who have practiced similar problems.
Spec1.06f Laws of logarithms: addition, subtraction, power rules4.01a Mathematical induction: construct proofs

  1. Prove by induction that for all positive integers \(n\)
$$\sum _ { r = 1 } ^ { n } \log ( 2 r - 1 ) = \log \left( \frac { ( 2 n ) ! } { 2 ^ { n } n ! } \right)$$

\begin{enumerate}
  \item Prove by induction that for all positive integers $n$
\end{enumerate}

$$\sum _ { r = 1 } ^ { n } \log ( 2 r - 1 ) = \log \left( \frac { ( 2 n ) ! } { 2 ^ { n } n ! } \right)$$

\hfill \mbox{\textit{Edexcel F1 2023 Q9 [6]}}