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\includegraphics[max width=\textwidth, alt={}, center]{ccadf73b-16f5-463a-8f69-1394839d5325-2_346_437_1155_854}
The diagram shows a variable point \(P\) with coordinates \(( x , y )\) and the point \(N\) which is the foot of the perpendicular from \(P\) to the \(x\)-axis. \(P\) moves on a curve such that, for all \(x \geqslant 0\), the gradient of the curve is equal in value to the area of the triangle \(O P N\), where \(O\) is the origin.
- State a differential equation satisfied by \(x\) and \(y\).
The point with coordinates \(( 0,2 )\) lies on the curve.
- Solve the differential equation to obtain the equation of the curve, expressing \(y\) in terms of \(x\).
- Sketch the curve.