Edexcel C3 2013 June — Question 6 9 marks

Exam BoardEdexcel
ModuleC3 (Core Mathematics 3)
Year2013
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFunction Transformations
TypeComposite transformation sketch
DifficultyModerate -0.3 This is a straightforward piecewise function question requiring standard techniques: reading range from a graph, function composition with simple substitution, solving linear and exponential equations, and stating a basic inverse function criterion. All parts are routine C3 exercises with no novel problem-solving required, making it slightly easier than average.
Spec1.02n Sketch curves: simple equations including polynomials1.02u Functions: definition and vocabulary (domain, range, mapping)1.02v Inverse and composite functions: graphs and conditions for existence1.06a Exponential function: a^x and e^x graphs and properties

6. \begin{figure}[h]
\includegraphics[width=\textwidth]{0f6fd881-4d4b-4f80-96cc-6da41cc33c60-10_775_1392_233_278} \caption{Figure 3}
\end{figure} Figure 3 shows a sketch of the graph of \(y = \mathrm { f } ( x )\) where $$\mathrm { f } ( x ) = \left\{ \begin{array} { r r } 5 - 2 x , & x \leqslant 4 \\ \mathrm { e } ^ { 2 x - 8 } - 4 , & x > 4 \end{array} \right.$$
  1. State the range of \(\mathrm { f } ( x )\).
  2. Determine the exact value of ff(0).
  3. Solve \(\mathrm { f } ( x ) = 21\) Give each answer as an exact answer.
  4. Explain why the function f does not have an inverse.

AnswerMarks
(a) \(f(x) \geq -3\)B1
(b) \(f(0) = 5\) or attempts to put their \(f(0)\) into \(e^{2x - 8} - 4\)M1
Correct answer \(f(0) = e^2 - 4\)A1
(c) Either \(5 - 2x = 21 \Rightarrow x = -8\)M1, A1
Or \(e^{2x - 8} - 4 = 21\)M1
Correct order and \(\ln\) work \(\Rightarrow x = \frac{\ln 25 + 8}{2}\) or \(x = \frac{\ln 5 + 4}{2}\) or equivalentM1, A1
(d) \(f\) does not have an inverse as it is a 'many to one' functionB1
Accept: \(f\) does not have an inverse as it is not a 'one to one' function
(a) $f(x) \geq -3$ | B1

(b) $f(0) = 5$ or attempts to put their $f(0)$ into $e^{2x - 8} - 4$ | M1
Correct answer $f(0) = e^2 - 4$ | A1

(c) Either $5 - 2x = 21 \Rightarrow x = -8$ | M1, A1
Or $e^{2x - 8} - 4 = 21$ | M1
Correct order and $\ln$ work $\Rightarrow x = \frac{\ln 25 + 8}{2}$ or $x = \frac{\ln 5 + 4}{2}$ or equivalent | M1, A1

(d) $f$ does not have an inverse as it is a 'many to one' function | B1
Accept: $f$ does not have an inverse as it is not a 'one to one' function |

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6.

\begin{figure}[h]
\begin{center}
  \includegraphics[width=\textwidth]{0f6fd881-4d4b-4f80-96cc-6da41cc33c60-10_775_1392_233_278}
\caption{Figure 3}
\end{center}
\end{figure}

Figure 3 shows a sketch of the graph of $y = \mathrm { f } ( x )$ where

$$\mathrm { f } ( x ) = \left\{ \begin{array} { r r } 
5 - 2 x , & x \leqslant 4 \\
\mathrm { e } ^ { 2 x - 8 } - 4 , & x > 4
\end{array} \right.$$
\begin{enumerate}[label=(\alph*)]
\item State the range of $\mathrm { f } ( x )$.
\item Determine the exact value of ff(0).
\item Solve $\mathrm { f } ( x ) = 21$

Give each answer as an exact answer.
\item Explain why the function f does not have an inverse.
\end{enumerate}

\hfill \mbox{\textit{Edexcel C3 2013 Q6 [9]}}