Edexcel C3 2009 January — Question 5 10 marks

Exam BoardEdexcel
ModuleC3 (Core Mathematics 3)
Year2009
SessionJanuary
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComposite & Inverse Functions
TypeVerify composite identity
DifficultyModerate -0.3 This is a straightforward composite function question requiring routine application of standard techniques: identifying ranges (trivial for exponential functions), substituting one function into another, and differentiating using chain rule. Part (b) is a 'show that' verification rather than independent derivation, and part (d) involves basic differentiation and solving a simple equation. All parts are textbook-standard with no novel insight required, making it slightly easier than average.
Spec1.02u Functions: definition and vocabulary (domain, range, mapping)1.07r Chain rule: dy/dx = dy/du * du/dx and connected rates

5. The functions \(f\) and \(g\) are defined by $$\begin{aligned} & \mathrm { f } : x \mapsto 3 x + \ln x , \quad x > 0 , \quad x \in \mathbb { R } \\ & \mathrm {~g} : x \mapsto \mathrm { e } ^ { x ^ { 2 } } , \quad x \in \mathbb { R } \end{aligned}$$
  1. Write down the range of g.
  2. Show that the composite function fg is defined by $$\mathrm { fg } : x \mapsto x ^ { 2 } + 3 \mathrm { e } ^ { x ^ { 2 } } , \quad x \in \mathbb { R } .$$
  3. Write down the range of fg.
  4. Solve the equation \(\frac { \mathrm { d } } { \mathrm { d } x } [ \mathrm { fg } ( x ) ] = x \left( x \mathrm { e } ^ { x ^ { 2 } } + 2 \right)\).

(a)
AnswerMarks Guidance
\(g(x) \geq 1\)B1 (1)
(b)
AnswerMarks Guidance
\(f \circ g(x) = f(e^{x^2}) = 3e^{x^2} + \ln e^{x^2}\)M1
\(= x^2 + 3e^{x^2}\)cso A1
(fg: \(x \mapsto x^2 + 3e^{x^2}\))
(c)
AnswerMarks Guidance
\(fg(x) \geq 3\)B1 (1)
(d)
AnswerMarks Guidance
\(\frac{d}{dx}(x^2 + 3e^{x^2}) = 2x + 6xe^{x^2}\)M1 A1
\(2x + 6xe^{x^2} = x^2e^{x^2} + 2x\)M1
\(e^{x^2}(6x - x^2) = 0\)M1
\(e^{x^2} \neq 0\), \(6x - x^2 = 0\)A1
\(x = 0, 6\)A1 A1 (6) [10]
**(a)**

$g(x) \geq 1$ | B1 | (1)

**(b)**

$f \circ g(x) = f(e^{x^2}) = 3e^{x^2} + \ln e^{x^2}$ | M1

$= x^2 + 3e^{x^2}$ | cso | A1 | (2)
(fg: $x \mapsto x^2 + 3e^{x^2}$)

**(c)**

$fg(x) \geq 3$ | B1 | (1)

**(d)**

$\frac{d}{dx}(x^2 + 3e^{x^2}) = 2x + 6xe^{x^2}$ | M1 A1

$2x + 6xe^{x^2} = x^2e^{x^2} + 2x$ | M1

$e^{x^2}(6x - x^2) = 0$ | M1

$e^{x^2} \neq 0$, $6x - x^2 = 0$ | A1

$x = 0, 6$ | A1 A1 | (6) [10]

---
5. The functions $f$ and $g$ are defined by

$$\begin{aligned}
& \mathrm { f } : x \mapsto 3 x + \ln x , \quad x > 0 , \quad x \in \mathbb { R } \\
& \mathrm {~g} : x \mapsto \mathrm { e } ^ { x ^ { 2 } } , \quad x \in \mathbb { R }
\end{aligned}$$
\begin{enumerate}[label=(\alph*)]
\item Write down the range of g.
\item Show that the composite function fg is defined by

$$\mathrm { fg } : x \mapsto x ^ { 2 } + 3 \mathrm { e } ^ { x ^ { 2 } } , \quad x \in \mathbb { R } .$$
\item Write down the range of fg.
\item Solve the equation $\frac { \mathrm { d } } { \mathrm { d } x } [ \mathrm { fg } ( x ) ] = x \left( x \mathrm { e } ^ { x ^ { 2 } } + 2 \right)$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel C3 2009 Q5 [10]}}