Edexcel C2 2006 January — Question 8 9 marks

Exam BoardEdexcel
ModuleC2 (Core Mathematics 2)
Year2006
SessionJanuary
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTrigonometric equations in context
TypeSolve shifted trig equation
DifficultyModerate -0.8 Two straightforward C2 trig equations requiring standard techniques: (a) isolate sin, find reference angle, apply phase shift; (b) take square root, find tan values. Both are routine textbook exercises with no problem-solving insight needed, making them easier than average A-level questions.
Spec1.05o Trigonometric equations: solve in given intervals

  1. (a) Find all the values of \(\theta\), to 1 decimal place, in the interval \(0 ^ { \circ } \leqslant \theta < 360 ^ { \circ }\) for which
$$5 \sin \left( \theta + 30 ^ { \circ } \right) = 3$$ (b) Find all the values of \(\theta\), to 1 decimal place, in the interval \(0 ^ { \circ } \leqslant \theta < 360 ^ { \circ }\) for which $$\tan ^ { 2 } \theta = 4$$

AnswerMarks Guidance
(a) \(\sin(\theta+30) = \frac{3}{5}\)B1 (\(\frac{3}{5}\) on RHS)
\(\theta + 30 = 36.9\)B1 (\(\alpha =\) AWRT 37)
or \(= 143.1\)M1 (\((180-\alpha)\))
\(\theta = 6.9, 113.1\)A1 cao (4 marks)
(b) \(\tan\theta = \pm 2\) or \(\sin\theta = \pm\frac{2}{\sqrt{5}}\) or \(\cos\theta = \pm\frac{1}{\sqrt{5}}\)B1
\((\tan\theta = 2 \Rightarrow)\) \(\theta = 63.4\)B1 (\(\beta =\) AWRT 63.4)
or \(243.4\)M1 (\((180+\beta)\))
\((\tan\theta = -2 \Rightarrow)\) \(\theta = 116.6\)M1 (\((180-\beta)\))
or \(296.6\)M1 (\((180+\) their \(116.6)\)) (5 marks)
Guidance:
- (a) M1 for \(180 -\) their first solution. Must be at the correct stage i.e. for \(\theta+30\)
- (b) ALL M marks in (b) must be for \(\theta = \ldots\)
- 1st M1 for \(180 +\) their first solution
- 2nd M1 for \(180 -\) their first solution
- 3rd M1 for \(180+\) their 116.6 or \(360 -\) their first solution
Answers Only can score full marks in both parts
Not 1 d.p.: loses A1 in part (a). In (b) all answers are AWRT.
Ignore extra solutions outside range
Radians: Allow M marks for consistent work with radians only, but all A and B marks for angles must be in degrees. Mixing degrees and radians is M0.
Total: 9 marks
(a) $\sin(\theta+30) = \frac{3}{5}$ | B1 ($\frac{3}{5}$ on RHS)
$\theta + 30 = 36.9$ | B1 ($\alpha =$ AWRT 37)
or $= 143.1$ | M1 ($(180-\alpha)$)
$\theta = 6.9, 113.1$ | A1 cao | (4 marks)

(b) $\tan\theta = \pm 2$ or $\sin\theta = \pm\frac{2}{\sqrt{5}}$ or $\cos\theta = \pm\frac{1}{\sqrt{5}}$ | B1
$(\tan\theta = 2 \Rightarrow)$ $\theta = 63.4$ | B1 ($\beta =$ AWRT 63.4)
or $243.4$ | M1 ($(180+\beta)$)
$(\tan\theta = -2 \Rightarrow)$ $\theta = 116.6$ | M1 ($(180-\beta)$)
or $296.6$ | M1 ($(180+$ their $116.6)$) | (5 marks)

**Guidance:**
- (a) M1 for $180 -$ their first solution. Must be at the correct stage i.e. for $\theta+30$
- (b) ALL M marks in (b) must be for $\theta = \ldots$
  - 1st M1 for $180 +$ their first solution
  - 2nd M1 for $180 -$ their first solution
  - 3rd M1 for $180+$ their 116.6 or $360 -$ their first solution

**Answers Only** can score full marks in both parts

**Not 1 d.p.:** loses A1 in part (a). In (b) all answers are AWRT.

**Ignore extra solutions outside range**

**Radians:** Allow M marks for consistent work with radians only, but all A and B marks for angles must be in degrees. Mixing degrees and radians is M0.

**Total: 9 marks**

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\begin{enumerate}
  \item (a) Find all the values of $\theta$, to 1 decimal place, in the interval $0 ^ { \circ } \leqslant \theta < 360 ^ { \circ }$ for which
\end{enumerate}

$$5 \sin \left( \theta + 30 ^ { \circ } \right) = 3$$

(b) Find all the values of $\theta$, to 1 decimal place, in the interval $0 ^ { \circ } \leqslant \theta < 360 ^ { \circ }$ for which

$$\tan ^ { 2 } \theta = 4$$

\hfill \mbox{\textit{Edexcel C2 2006 Q8 [9]}}