Edexcel C1 2011 January — Question 10 8 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Year2011
SessionJanuary
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCurve Sketching
TypeRational curve intersections
DifficultyModerate -0.3 This is a straightforward C1 curve sketching question requiring students to sketch a cubic (by finding roots and considering end behavior) and a reciprocal function, then count intersections. While it involves multiple steps, each component uses standard techniques with no novel problem-solving required—slightly easier than average due to the routine nature of the tasks.
Spec1.02n Sketch curves: simple equations including polynomials1.02o Sketch reciprocal curves: y=a/x and y=a/x^21.02q Use intersection points: of graphs to solve equations

10. (a) On the axes below, sketch the graphs of
  1. \(y = x ( x + 2 ) ( 3 - x )\)
  2. \(y = - \frac { 2 } { x }\) showing clearly the coordinates of all the points where the curves cross the coordinate axes.
    (b) Using your sketch state, giving a reason, the number of real solutions to the equation $$x ( x + 2 ) ( 3 - x ) + \frac { 2 } { x } = 0$$ \includegraphics[max width=\textwidth, alt={}, center]{95e11fd7-765c-477d-800b-7574bc1af81f-13_994_997_1270_479}

Question 10:
Part (a):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Correct shape (negative cubic)B1
Crossing at \((-2, 0)\)B1
Through the originB1
Crossing at \((3, 0)\)B1
2 branches in correct quadrants not crossing axesB1
One intersection with cubic on each branchB1
(6)
Part (b):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
"2" solutionsB1ft For a value compatible with their sketch. Only allow 0, 2 or 4
Since only "2" intersectionsdB1ft Dependent on value being compatible with sketch. Comment relating number of solutions to number of intersections
(2)
## Question 10:

### Part (a):

| Answer/Working | Marks | Guidance |
|---|---|---|
| Correct shape (negative cubic) | B1 | |
| Crossing at $(-2, 0)$ | B1 | |
| Through the origin | B1 | |
| Crossing at $(3, 0)$ | B1 | |
| 2 branches in correct quadrants not crossing axes | B1 | |
| One intersection with cubic on each branch | B1 | |
| | **(6)** | |

### Part (b):

| Answer/Working | Marks | Guidance |
|---|---|---|
| "2" solutions | B1ft | For a value compatible with their sketch. Only allow 0, 2 or 4 |
| Since only "2" intersections | dB1ft | Dependent on value being compatible with sketch. Comment relating number of solutions to number of intersections |
| | **(2)** | |

---
10. (a) On the axes below, sketch the graphs of
\begin{enumerate}[label=(\roman*)]
\item $y = x ( x + 2 ) ( 3 - x )$
\item $y = - \frac { 2 } { x }$\\
showing clearly the coordinates of all the points where the curves cross the coordinate axes.\\
(b) Using your sketch state, giving a reason, the number of real solutions to the equation

$$x ( x + 2 ) ( 3 - x ) + \frac { 2 } { x } = 0$$

\includegraphics[max width=\textwidth, alt={}, center]{95e11fd7-765c-477d-800b-7574bc1af81f-13_994_997_1270_479}
\end{enumerate}

\hfill \mbox{\textit{Edexcel C1 2011 Q10 [8]}}