Edexcel C1 2011 January — Question 6 7 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Year2011
SessionJanuary
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicArithmetic Sequences and Series
TypeArithmetic progression with parameters
DifficultyModerate -0.8 This is a straightforward application of standard arithmetic sequence formulas (S_n and nth term). Part (a) is a 'show that' requiring direct substitution into the sum formula, while parts (b) and (c) involve forming and solving simultaneous linear equations—all routine procedures for C1 with no problem-solving insight required.
Spec1.04h Arithmetic sequences: nth term and sum formulae

6. An arithmetic sequence has first term \(a\) and common difference \(d\). The sum of the first 10 terms of the sequence is 162 .
  1. Show that \(10 a + 45 d = 162\) Given also that the sixth term of the sequence is 17 ,
  2. write down a second equation in \(a\) and \(d\),
  3. find the value of \(a\) and the value of \(d\).

Question 6:
Part (a):
AnswerMarks Guidance
\(S_{10} = \dfrac{10}{2}[2a + 9d]\) or expansion giving \(162 = 10a + 45d\)M1, A1cso M1 for use of \(S_n\) with \(n=10\)
(2 marks total)
Part (b):
AnswerMarks Guidance
\((u_n = a+(n-1)d \Rightarrow)\ 17 = a + 5d\)B1
\(10 \times (b)\) gives \(10a + 50d = 170\); (a) is \(10a + 45d = 162\)M1 For attempt to eliminate \(a\) or \(d\) from their two linear equations
Subtract: \(5d = 8\), so \(d = \underline{1.6}\) o.e.A1
Solving for \(a\): \(a = 17 - 5d\)M1 For using their value of \(a\) or \(d\) to find the other value
so \(a = \underline{9}\)A1
(4 marks total)
## Question 6:

### Part (a):
| $S_{10} = \dfrac{10}{2}[2a + 9d]$ or expansion giving $162 = 10a + 45d$ | M1, A1cso | M1 for use of $S_n$ with $n=10$ |
|(2 marks total)|||

### Part (b):
| $(u_n = a+(n-1)d \Rightarrow)\ 17 = a + 5d$ | B1 | |
| $10 \times (b)$ gives $10a + 50d = 170$; (a) is $10a + 45d = 162$ | M1 | For attempt to eliminate $a$ or $d$ from their two linear equations |
| Subtract: $5d = 8$, so $d = \underline{1.6}$ o.e. | A1 | |
| Solving for $a$: $a = 17 - 5d$ | M1 | For using their value of $a$ or $d$ to find the other value |
| so $a = \underline{9}$ | A1 | |
|(4 marks total)|||

---
6. An arithmetic sequence has first term $a$ and common difference $d$. The sum of the first 10 terms of the sequence is 162 .
\begin{enumerate}[label=(\alph*)]
\item Show that $10 a + 45 d = 162$

Given also that the sixth term of the sequence is 17 ,
\item write down a second equation in $a$ and $d$,
\item find the value of $a$ and the value of $d$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel C1 2011 Q6 [7]}}