Edexcel C1 2011 January — Question 1 4 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Year2011
SessionJanuary
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIndices and Surds
TypeSimplify algebraic expressions with indices
DifficultyEasy -1.3 This is a straightforward C1 indices question requiring only direct application of index laws with no problem-solving. Part (a) is basic numerical evaluation of a negative fractional power, and part (b) applies the power rule mechanically to simplify an expression. Both parts are routine drill exercises below average A-level difficulty.
Spec1.02a Indices: laws of indices for rational exponents

  1. Find the value of \(16 ^ { - \frac { 1 } { 4 } }\)
  2. Simplify \(x \left( 2 x ^ { - \frac { 1 } { 4 } } \right) ^ { 4 }\)

Question 1:
Part (a)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(16^{\frac{1}{4}} = 2\) or \(\frac{1}{16^{\frac{1}{4}}}\) or betterM1 For a correct statement dealing with the \(\frac{1}{4}\) or the \(-\) power. Award if 2 is seen or for reciprocal of their \(16^{\frac{1}{4}}\). s.c. \(\frac{1}{4}\) is M1A0, \(2^{-1}\) is M1A0
\(16^{-\frac{1}{4}} = \frac{1}{2}\) or \(0.5\) (ignore \(\pm\))A1 \(\pm\frac{1}{2}\) is not penalised so M1A1
(2)
Part (b)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\left(2x^{-\frac{1}{4}}\right)^4 = 2^4 x^{-\frac{4}{4}}\) or \(\frac{2^4}{x^{\frac{4}{4}}}\) or equivalentM1 For correct use of the power 4 on both the 2 and the \(x\) terms
\(x\left(2x^{-\frac{1}{4}}\right)^4 = 2^4\) or \(16\)A1 cao For cancelling the \(x\) and simplifying to one of these two forms. Correct answers with no working get full marks
(2)
## Question 1:

### Part (a)

| Answer/Working | Marks | Guidance |
|---|---|---|
| $16^{\frac{1}{4}} = 2$ or $\frac{1}{16^{\frac{1}{4}}}$ or better | M1 | For a correct statement dealing with the $\frac{1}{4}$ or the $-$ power. Award if 2 is seen or for reciprocal of their $16^{\frac{1}{4}}$. s.c. $\frac{1}{4}$ is M1A0, $2^{-1}$ is M1A0 |
| $16^{-\frac{1}{4}} = \frac{1}{2}$ or $0.5$ (ignore $\pm$) | A1 | $\pm\frac{1}{2}$ is not penalised so M1A1 |
| | **(2)** | |

### Part (b)

| Answer/Working | Marks | Guidance |
|---|---|---|
| $\left(2x^{-\frac{1}{4}}\right)^4 = 2^4 x^{-\frac{4}{4}}$ or $\frac{2^4}{x^{\frac{4}{4}}}$ or equivalent | M1 | For **correct** use of the power 4 on both the 2 and the $x$ terms |
| $x\left(2x^{-\frac{1}{4}}\right)^4 = 2^4$ or $16$ | A1 cao | For cancelling the $x$ and simplifying to one of these two forms. Correct answers with no working get full marks |
| | **(2)** | |

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\begin{enumerate}[label=(\alph*)]
\item Find the value of $16 ^ { - \frac { 1 } { 4 } }$
\item Simplify $x \left( 2 x ^ { - \frac { 1 } { 4 } } \right) ^ { 4 }$
\end{enumerate}

\hfill \mbox{\textit{Edexcel C1 2011 Q1 [4]}}