Edexcel C1 2006 January — Question 2 4 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Year2006
SessionJanuary
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicArithmetic Sequences and Series
TypePeriodic or repeating sequence
DifficultyModerate -0.8 This is a straightforward recursive sequence question requiring simple arithmetic calculations. Part (a) involves three direct substitutions with basic operations (subtraction and squaring). Part (b) requires recognizing the pattern repeats (1→4→1), making u_20 trivial to find. No problem-solving insight needed beyond pattern recognition, making it easier than average C1 material.
Spec1.04e Sequences: nth term and recurrence relations

2. The sequence of positive numbers \(u _ { 1 } , u _ { 2 } , u _ { 3 } , \ldots\) is given by: $$u _ { n + 1 } = \left( u _ { n } - 3 \right) ^ { 2 } , \quad u _ { 1 } = 1 .$$
  1. Find \(u _ { 2 } , u _ { 3 }\) and \(u _ { 4 }\).
  2. Write down the value of \(u _ { 20 }\).

AnswerMarks
(a) \(u_2 = (-2)^2 = 4\)B1
\(u_3 = 1, u_4 = 4\) for \(u_3\), ft \((u_2-3)^2\)B1ft, B1
(b) \(u_{30} = 4\)B1ft
Total: 4 marks
AnswerMarks
Guidance: (b) ft only if sequence is "oscillating". Do not give marks if answers have clearly been obtained from wrong working, e.g. \(u_2 = (3-3)^2 = 0\), \(u_3 = (4-3)^2 = 1\), \(u_4 = (5-3)^2 = 4\).
**(a)** $u_2 = (-2)^2 = 4$ | B1 |

$u_3 = 1, u_4 = 4$ for $u_3$, ft $(u_2-3)^2$ | B1ft, B1 |

**(b)** $u_{30} = 4$ | B1ft |

**Total: 4 marks**

| Guidance: (b) ft only if sequence is "oscillating". Do not give marks if answers have clearly been obtained from wrong working, e.g. $u_2 = (3-3)^2 = 0$, $u_3 = (4-3)^2 = 1$, $u_4 = (5-3)^2 = 4$.

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2. The sequence of positive numbers $u _ { 1 } , u _ { 2 } , u _ { 3 } , \ldots$ is given by:

$$u _ { n + 1 } = \left( u _ { n } - 3 \right) ^ { 2 } , \quad u _ { 1 } = 1 .$$
\begin{enumerate}[label=(\alph*)]
\item Find $u _ { 2 } , u _ { 3 }$ and $u _ { 4 }$.
\item Write down the value of $u _ { 20 }$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel C1 2006 Q2 [4]}}