Edexcel C1 2006 January — Question 5 6 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Year2006
SessionJanuary
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIndices and Surds
TypeRationalize denominator simple
DifficultyEasy -1.8 This is a routine C1 question testing basic surd manipulation: simplifying √45 requires factorizing under the root, and rationalizing the denominator is a standard textbook exercise using conjugate multiplication. Both parts are direct application of memorized techniques with no problem-solving required.
Spec1.02b Surds: manipulation and rationalising denominators

5. (a) Write \(\sqrt { 45 }\) in the form \(a \sqrt { 5 }\), where \(a\) is an integer.
(b) Express \(\frac { 2 ( 3 + \sqrt { 5 } ) } { ( 3 - \sqrt { 5 } ) }\) in the form \(b + c \sqrt { 5 }\), where \(b\) and \(c\) are integers.
\section*{6.} \begin{figure}[h]
\captionsetup{labelformat=empty} \caption{Figure 1} \includegraphics[alt={},max width=\textwidth]{815e288c-0140-4c12-9e89-b0bb4fb1a8c1-07_607_844_310_555}
\end{figure} Figure 1 shows a sketch of the curve with equation \(y = \mathrm { f } ( x )\). The curve passes through the points \(( 0,3 )\) and \(( 4,0 )\) and touches the \(x\)-axis at the point \(( 1,0 )\). On separate diagrams sketch the curve with equation

AnswerMarks Guidance
(a) \(3\sqrt{5}\) (or \(a = 3\))B1
(b) \(\frac{2(3 + \sqrt{5})}{(3-\sqrt{5})} \times \frac{(3+\sqrt{5})}{(3+\sqrt{5})}\)M1
\((3-\sqrt{5})(3+\sqrt{5}) = 9 - 5 = 4\) (Used as or intended as denominator)B1
\((3+\sqrt{5})(p \pm q\sqrt{5}) = \ldots 4\) terms (\(p \neq 0, q \neq 0\)) (Independent)M1
or \((6 + 2\sqrt{5})(p \pm q\sqrt{5}) = \ldots 4\) terms (\(p \neq 0, q \neq 0\))
[Correct version: \((3+\sqrt{5})(3+\sqrt{5}) = 9 + 3\sqrt{5} + 3\sqrt{5} + 5\), or double this.]
\(\frac{2(14 + 6\sqrt{5})}{4} = 7 + 3\sqrt{5}\)A1 A1 1st A1: \(b = 7\), 2nd A1: \(c = 3\)
Total: 6 marks
AnswerMarks
Guidance: (b) 2nd M mark for attempting \((3+\sqrt{5})(p + q\sqrt{5})\) is generous. Condone errors.
**(a)** $3\sqrt{5}$ (or $a = 3$) | B1 |

**(b)** $\frac{2(3 + \sqrt{5})}{(3-\sqrt{5})} \times \frac{(3+\sqrt{5})}{(3+\sqrt{5})}$ | M1 |

$(3-\sqrt{5})(3+\sqrt{5}) = 9 - 5 = 4$ (Used as or intended as denominator) | B1 |

$(3+\sqrt{5})(p \pm q\sqrt{5}) = \ldots 4$ terms ($p \neq 0, q \neq 0$) (Independent) | M1 |

or $(6 + 2\sqrt{5})(p \pm q\sqrt{5}) = \ldots 4$ terms ($p \neq 0, q \neq 0$) |  |

[Correct version: $(3+\sqrt{5})(3+\sqrt{5}) = 9 + 3\sqrt{5} + 3\sqrt{5} + 5$, or double this.] |  |

$\frac{2(14 + 6\sqrt{5})}{4} = 7 + 3\sqrt{5}$ | A1 A1 | 1st A1: $b = 7$, 2nd A1: $c = 3$

**Total: 6 marks**

| Guidance: (b) 2nd M mark for attempting $(3+\sqrt{5})(p + q\sqrt{5})$ is generous. Condone errors.

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5. (a) Write $\sqrt { 45 }$ in the form $a \sqrt { 5 }$, where $a$ is an integer.\\
(b) Express $\frac { 2 ( 3 + \sqrt { 5 } ) } { ( 3 - \sqrt { 5 } ) }$ in the form $b + c \sqrt { 5 }$, where $b$ and $c$ are integers.\\

\section*{6.}
\begin{figure}[h]
\begin{center}
\captionsetup{labelformat=empty}
\caption{Figure 1}
  \includegraphics[alt={},max width=\textwidth]{815e288c-0140-4c12-9e89-b0bb4fb1a8c1-07_607_844_310_555}
\end{center}
\end{figure}

Figure 1 shows a sketch of the curve with equation $y = \mathrm { f } ( x )$. The curve passes through the points $( 0,3 )$ and $( 4,0 )$ and touches the $x$-axis at the point $( 1,0 )$.

On separate diagrams sketch the curve with equation\\

\hfill \mbox{\textit{Edexcel C1 2006 Q5 [6]}}