CAIE P1 2009 November — Question 3 6 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2009
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Theorem (positive integer n)
TypeProduct with unknown constant to determine
DifficultyModerate -0.3 Part (i) is straightforward binomial expansion requiring recall of the formula and basic arithmetic. Part (ii) requires collecting terms to find the x² coefficient and solving for a constant, which is a standard textbook exercise with minimal problem-solving demand. The question is slightly easier than average due to small powers and straightforward algebra.
Spec1.04a Binomial expansion: (a+b)^n for positive integer n

3
  1. Find the first 3 terms in the expansion of \(( 2 - x ) ^ { 6 }\) in ascending powers of \(x\).
  2. Given that the coefficient of \(x ^ { 2 }\) in the expansion of \(\left( 1 + 2 x + a x ^ { 2 } \right) ( 2 - x ) ^ { 6 }\) is 48 , find the value of the constant \(a\).

(i) \((2 – x)^6\)
M1: \(64 − 192x + 240x^2\)
M1: Allow \(2^6\)
A1: Considers at least 2 terms in \(x^2\)
[3]
(ii) \((1 + 2x + ax^2)(2 – x)^6\)
M1: Coeff of \(x^2 = 240 − 384 + 64a\)
M1: Considers exactly 3 terms + solution
A1: Equates to 48 \(\to a = 3\)
[3]
(i) $(2 – x)^6$

M1: $64 − 192x + 240x^2$

M1: Allow $2^6$

A1: Considers at least 2 terms in $x^2$

[3]

(ii) $(1 + 2x + ax^2)(2 – x)^6$

M1: Coeff of $x^2 = 240 − 384 + 64a$

M1: Considers exactly 3 terms + solution

A1: Equates to 48 $\to a = 3$

[3]
3 (i) Find the first 3 terms in the expansion of $( 2 - x ) ^ { 6 }$ in ascending powers of $x$.\\
(ii) Given that the coefficient of $x ^ { 2 }$ in the expansion of $\left( 1 + 2 x + a x ^ { 2 } \right) ( 2 - x ) ^ { 6 }$ is 48 , find the value of the constant $a$.

\hfill \mbox{\textit{CAIE P1 2009 Q3 [6]}}