CAIE P1 2009 November — Question 1 4 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2009
SessionNovember
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard trigonometric equations
TypeTransformed argument solving
DifficultyModerate -0.8 This is a straightforward transformed argument trigonometric equation requiring only basic algebraic manipulation (divide by 3, take arctan) and consideration of the periodic nature of tan within the transformed domain. The transformation is simple (linear) and the question is a standard textbook exercise with no conceptual challenges beyond routine application of inverse trig and period adjustment.
Spec1.05o Trigonometric equations: solve in given intervals

1 Solve the equation \(3 \tan \left( 2 x + 15 ^ { \circ } \right) = 4\) for \(0 ^ { \circ } \leqslant x \leqslant 180 ^ { \circ }\).

1 Solve the equation $3 \tan \left( 2 x + 15 ^ { \circ } \right) = 4$ for $0 ^ { \circ } \leqslant x \leqslant 180 ^ { \circ }$.

\hfill \mbox{\textit{CAIE P1 2009 Q1 [4]}}