Edexcel C12 2017 June — Question 7 7 marks

Exam BoardEdexcel
ModuleC12 (Core Mathematics 1 & 2)
Year2017
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCurve Sketching
TypeSketch transformed curve from description
DifficultyModerate -0.8 This is a straightforward transformations question testing standard Core 1/2 knowledge. Parts (a)-(c) require direct application of transformation rules (horizontal stretch, vertical translation, reading from graph), while part (d) is a routine reflection in the x-axis. All transformations are basic with no problem-solving or novel insight required.
Spec1.02w Graph transformations: simple transformations of f(x)

7. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{08b1be3e-2d9a-4832-b230-d5519540f494-20_588_839_219_550} \captionsetup{labelformat=empty} \caption{Figure 3}
\end{figure} Figure 3 shows a sketch of part of the curve with equation \(y = \mathrm { f } ( x )\). The curve crosses the \(y\)-axis at the point \(( 0,8 )\). The line with equation \(y = 10\) is the only asymptote to the curve.
The curve has a single turning point, a minimum point at \(( 2,5 )\), as shown in Figure 3.
  1. State the coordinates of the minimum point of the curve with equation \(y = \mathrm { f } \left( \frac { 1 } { 4 } x \right)\)
  2. State the equation of the asymptote to the curve with equation \(y = \mathrm { f } ( x ) - 3\) The curve with equation \(y = \mathrm { f } ( x )\) meets the line with equation \(y = k\), where \(k\) is a constant, at two distinct points.
  3. State the set of possible values for \(k\).
  4. Sketch the curve with equation \(y = - \mathrm { f } ( x )\). On your sketch, show clearly the coordinates of the turning point, the coordinates of the intersection with the \(y\)-axis and the equation of the asymptote. \section*{\textbackslash section*\{D\}}

Question 7 (Graph Transformations):
Part (a):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\((8, 5)\)B1 Accept \(x=8\), \(y=5\) or sketch of \(y=f\!\left(\frac{1}{4}x\right)\) with minimum marked at \((8,5)\)
Part (b):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(y = 7\)B1 Must be an equation, not just '\(7\)'
Part (c):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(5 < k < 10\)M1, A1 M1: accept one "side" of inequality, condoning misunderstanding of whether boundary included; allow \(k>5\), \(k\geq5\), \(k<10\), \(k\leq10\); condone different variable; A1: cao \(55\ \textbf{and}\ k<10\); \((5,10)\); \(\{k\in\mathbb{R}: 55\ \textbf{or}\ k<10\)
Part (d):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Shape (reflection in \(x\)-axis)B1 Look for shape shown in scheme; tolerant of slips at either end
\((0,-8)\) and \((2,-5)\) markedB1 Graph has intercept \((0,-8)\) and single maximum at \((2,-5)\); accept \(-8\) marked on \(y\)-axis; condone \((-8,0)\) if marked on correct axis
Asymptote \(y=-10\)B1 Graph must clearly be asymptotic; tolerant of slips
# Question 7 (Graph Transformations):

## Part (a):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $(8, 5)$ | B1 | Accept $x=8$, $y=5$ or sketch of $y=f\!\left(\frac{1}{4}x\right)$ with minimum marked at $(8,5)$ | **(1)** |

## Part (b):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $y = 7$ | B1 | Must be an equation, not just '$7$' | **(1)** |

## Part (c):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $5 < k < 10$ | M1, A1 | M1: accept one "side" of inequality, condoning misunderstanding of whether boundary included; allow $k>5$, $k\geq5$, $k<10$, $k\leq10$; condone different variable; A1: cao $5<k<10$; allow $k>5\ \textbf{and}\ k<10$; $(5,10)$; $\{k\in\mathbb{R}: 5<k<10\}$; do not allow $k>5\ \textbf{or}\ k<10$ | **(2)** |

## Part (d):
| Answer/Working | Marks | Guidance |
|---|---|---|
| Shape (reflection in $x$-axis) | B1 | Look for shape shown in scheme; tolerant of slips at either end |
| $(0,-8)$ and $(2,-5)$ marked | B1 | Graph has intercept $(0,-8)$ and single **maximum** at $(2,-5)$; accept $-8$ marked on $y$-axis; condone $(-8,0)$ if marked on correct axis |
| Asymptote $y=-10$ | B1 | Graph must clearly be asymptotic; tolerant of slips | **(3)(7 marks)** |

---
7.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{08b1be3e-2d9a-4832-b230-d5519540f494-20_588_839_219_550}
\captionsetup{labelformat=empty}
\caption{Figure 3}
\end{center}
\end{figure}

Figure 3 shows a sketch of part of the curve with equation $y = \mathrm { f } ( x )$.

The curve crosses the $y$-axis at the point $( 0,8 )$.

The line with equation $y = 10$ is the only asymptote to the curve.\\
The curve has a single turning point, a minimum point at $( 2,5 )$, as shown in Figure 3.
\begin{enumerate}[label=(\alph*)]
\item State the coordinates of the minimum point of the curve with equation $y = \mathrm { f } \left( \frac { 1 } { 4 } x \right)$
\item State the equation of the asymptote to the curve with equation $y = \mathrm { f } ( x ) - 3$

The curve with equation $y = \mathrm { f } ( x )$ meets the line with equation $y = k$, where $k$ is a constant, at two distinct points.
\item State the set of possible values for $k$.
\item Sketch the curve with equation $y = - \mathrm { f } ( x )$. On your sketch, show clearly the coordinates of the turning point, the coordinates of the intersection with the $y$-axis and the equation of the asymptote.

\section*{\textbackslash section*\{D\}}
\end{enumerate}

\hfill \mbox{\textit{Edexcel C12 2017 Q7 [7]}}