Edexcel C12 2017 June — Question 2 4 marks

Exam BoardEdexcel
ModuleC12 (Core Mathematics 1 & 2)
Year2017
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIndices and Surds
TypeSimplify algebraic expressions with indices
DifficultyEasy -1.3 This is a straightforward Core 1/2 indices and surds question requiring only direct application of standard rules (power of 0.5, negative powers, rationalizing). Part (a) and (b) are routine index law applications, while (c) involves basic surd manipulation. No problem-solving or insight needed—purely procedural recall.
Spec1.02a Indices: laws of indices for rational exponents1.02b Surds: manipulation and rationalising denominators

  1. Simplify the following expressions fully.
    1. \(\left( \frac { 1 } { 9 } x ^ { 4 } \right) ^ { 0.5 }\)
    2. \(\left( \frac { x } { \sqrt { 2 } } \right) ^ { - 2 }\)
    3. \(x \sqrt { 3 } \div \sqrt { \frac { 48 } { x ^ { 4 } } }\)

Question 2:
(a)
AnswerMarks Guidance
\(\frac{1}{3}x^2\)B1 Accept exact alternatives like \(\frac{x^2}{3}\) and \(0.\dot{3}x^2\) but not \(0.33x^2\)
(b)
AnswerMarks Guidance
\(\left(\frac{x}{\sqrt{2}}\right)^{-2} = \frac{2}{x^2}\)B1 Accept exact alternatives such as \(2 \times x^{-2}\) or \(2 \times \frac{1}{x^2}\) (all forms must have a '2')
(c)
AnswerMarks Guidance
\(\sqrt{3}(x) \div \sqrt{\frac{48}{x^4}} = \frac{\sqrt{3}}{\sqrt{48}} \times x\sqrt{x^4} = \frac{1}{4}x^3\)M1 Either the correct coefficient (accept \(\frac{1}{4}\) or 0.25) or the correct power of \(x\) (accept \(x^3\) or \(\frac{1}{x^{-3}}\))
\(\frac{1}{4}x^3\)A1 Only accept \(\frac{1}{4}x^3\) or simplified equivalents such as \(0.25 \times x^3\). Do NOT accept \(\frac{1}{4x^{-3}}\)
## Question 2:

**(a)**
| $\frac{1}{3}x^2$ | B1 | Accept exact alternatives like $\frac{x^2}{3}$ and $0.\dot{3}x^2$ but not $0.33x^2$ |

**(b)**
| $\left(\frac{x}{\sqrt{2}}\right)^{-2} = \frac{2}{x^2}$ | B1 | Accept exact alternatives such as $2 \times x^{-2}$ or $2 \times \frac{1}{x^2}$ (all forms must have a '2') |

**(c)**
| $\sqrt{3}(x) \div \sqrt{\frac{48}{x^4}} = \frac{\sqrt{3}}{\sqrt{48}} \times x\sqrt{x^4} = \frac{1}{4}x^3$ | M1 | Either the correct coefficient (accept $\frac{1}{4}$ or 0.25) or the correct power of $x$ (accept $x^3$ or $\frac{1}{x^{-3}}$) |
| $\frac{1}{4}x^3$ | A1 | Only accept $\frac{1}{4}x^3$ or simplified equivalents such as $0.25 \times x^3$. Do NOT accept $\frac{1}{4x^{-3}}$ |

---
\begin{enumerate}
  \item Simplify the following expressions fully.\\
(a) $\left( \frac { 1 } { 9 } x ^ { 4 } \right) ^ { 0.5 }$\\
(b) $\left( \frac { x } { \sqrt { 2 } } \right) ^ { - 2 }$\\
(c) $x \sqrt { 3 } \div \sqrt { \frac { 48 } { x ^ { 4 } } }$
\end{enumerate}

\hfill \mbox{\textit{Edexcel C12 2017 Q2 [4]}}