CAIE S2 2020 Specimen — Question 7 7 marks

Exam BoardCAIE
ModuleS2 (Statistics 2)
Year2020
SessionSpecimen
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicZ-tests (known variance)
TypeTwo-tail z-test
DifficultyStandard +0.3 This is a straightforward two-tail z-test with given summary statistics. Students need to calculate the sample mean, use the given variance, compute a z-statistic, and compare to critical values at 1% significance level. It's slightly easier than average because it's a standard procedure with clear steps and no conceptual complications.
Spec5.05c Hypothesis test: normal distribution for population mean

7 The mean weight of bags of carrots is \(\mu\) kilograms. An inspector wishes to test whether \(\mu = 2.0\). He weighs a random sample of 200 bags and his results are summarised as follows. $$\Sigma x = 430 \quad \Sigma x ^ { 2 } = 1290$$ Carry out the test at the 10\% significance level.

Question 7:
AnswerMarks Guidance
AnswerMarks Guidance
\(H_0: \mu = 2.0\); \(H_1: \mu \neq 2.0\)B1
\(\bar{x} = \frac{430}{200} = 2.15\)B1 For \(\bar{x}\)
\(s^2 = \frac{200}{199}\left(\frac{1290}{200} - \left(\frac{430}{200}\right)^2\right)\)M1 Correct substitution in \(s^2\) formula
\(= 1.8366834\)A1 For \(s^2\) correct (or \(s = 1.35524\))
\(\frac{2.15 - 2.0}{\sqrt{1.8366834/200}}\ (= 1.565)\)M1 For standardising (need 200); accept standard deviation/variance mixes
\(z = 1.645\)M1 For correct comparison of \(z\) values or areas
No evidence that \(\mu \neq 2.0\)A1 Correct working only (condone biased variance for last 3 marks)
Total: 7
## Question 7:

| Answer | Marks | Guidance |
|--------|-------|----------|
| $H_0: \mu = 2.0$; $H_1: \mu \neq 2.0$ | B1 | |
| $\bar{x} = \frac{430}{200} = 2.15$ | B1 | For $\bar{x}$ |
| $s^2 = \frac{200}{199}\left(\frac{1290}{200} - \left(\frac{430}{200}\right)^2\right)$ | M1 | Correct substitution in $s^2$ formula |
| $= 1.8366834$ | A1 | For $s^2$ correct (or $s = 1.35524$) |
| $\frac{2.15 - 2.0}{\sqrt{1.8366834/200}}\ (= 1.565)$ | M1 | For standardising (need 200); accept standard deviation/variance mixes |
| $z = 1.645$ | M1 | For correct comparison of $z$ values or areas |
| No evidence that $\mu \neq 2.0$ | A1 | Correct working only (condone biased variance for last 3 marks) |
| **Total: 7** | | |
7 The mean weight of bags of carrots is $\mu$ kilograms. An inspector wishes to test whether $\mu = 2.0$. He weighs a random sample of 200 bags and his results are summarised as follows.

$$\Sigma x = 430 \quad \Sigma x ^ { 2 } = 1290$$

Carry out the test at the 10\% significance level.\\

\hfill \mbox{\textit{CAIE S2 2020 Q7 [7]}}