CAIE S2 2020 Specimen — Question 4 10 marks

Exam BoardCAIE
ModuleS2 (Statistics 2)
Year2020
SessionSpecimen
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicLinear combinations of normal random variables
TypeMultiple stage process probability
DifficultyStandard +0.8 This question requires understanding of linear combinations of independent normal random variables, including finding distributions of sums and differences with coefficients. Part (b) involves comparing 3Y - X which requires careful handling of variance scaling. This is a standard S2 topic but requires multiple steps and proper application of variance rules, making it moderately challenging but not exceptional for Further Maths Statistics.
Spec5.04a Linear combinations: E(aX+bY), Var(aX+bY)5.04b Linear combinations: of normal distributions

4 The lifetimes, in hours, of Longlive light bulbs and Enerlow light bulbs have the independent distributions \(\mathrm { N } \left( 1020,45 ^ { 2 } \right)\) and \(\mathrm { N } \left( 2800,52 ^ { 2 } \right)\) respectively.
  1. Find the probability that the total of the lifetimes of five randomly chosen Longlive bulbs is less than 5200 hours.
  2. Find the probability that the lifetime of a randomly chosen Enerlow bulb is at least three times that of a randomly chosen Longlive bulb.

Question 4(a):
AnswerMarks Guidance
AnswerMarks Guidance
\(N(5100,\ 5 \times 45^2)\) or \(N(5100, 10125)\)1, B1 Seen or implied
\(\dfrac{5200 - 5100'}{\sqrt{10125'}}\) \((= 0.994)\)1, M1 Standardising with their new mean and new variance
\(\Phi(0.994')\)1, M1 Area consistent with their working with normal
\(= 0.840\) (3 sf)1, A1
Total: 4
Question 4(b):
AnswerMarks Guidance
AnswerMarks Guidance
Use of \(E - 3L\) or similar1, M1
\(E(E - 3L) = -260\)1, B1 or \(2800 - 3 \times 1020\)
\(\text{Var}(E - 3L) = 52^2 + 9 \times 45^2\) or \(20929\)1, B1 Using a positive variance with \(45^2\) and \(52^2\) combined
\(\dfrac{0 - (-260')}{\sqrt{20929'}}\) \((= 1.797)\)1, M1
\(1 - \Phi(1.797')\)1, M1 Consistent area, must clearly be \(\Phi\)
\(= 0.0361\) (3 sf) or \(0.0362\)1, A1
Total: 6
## Question 4(a):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $N(5100,\ 5 \times 45^2)$ or $N(5100, 10125)$ | 1, B1 | Seen or implied |
| $\dfrac{5200 - 5100'}{\sqrt{10125'}}$ $(= 0.994)$ | 1, M1 | Standardising with their new mean and new variance |
| $\Phi(0.994')$ | 1, M1 | Area consistent with their working with normal |
| $= 0.840$ (3 sf) | 1, A1 | |
| **Total: 4** | | |

---

## Question 4(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Use of $E - 3L$ or similar | 1, M1 | |
| $E(E - 3L) = -260$ | 1, B1 | or $2800 - 3 \times 1020$ |
| $\text{Var}(E - 3L) = 52^2 + 9 \times 45^2$ or $20929$ | 1, B1 | Using a positive variance with $45^2$ and $52^2$ combined |
| $\dfrac{0 - (-260')}{\sqrt{20929'}}$ $(= 1.797)$ | 1, M1 | |
| $1 - \Phi(1.797')$ | 1, M1 | Consistent area, must clearly be $\Phi$ |
| $= 0.0361$ (3 sf) or $0.0362$ | 1, A1 | |
| **Total: 6** | | |
4 The lifetimes, in hours, of Longlive light bulbs and Enerlow light bulbs have the independent distributions $\mathrm { N } \left( 1020,45 ^ { 2 } \right)$ and $\mathrm { N } \left( 2800,52 ^ { 2 } \right)$ respectively.\\
(a) Find the probability that the total of the lifetimes of five randomly chosen Longlive bulbs is less than 5200 hours.\\
(b) Find the probability that the lifetime of a randomly chosen Enerlow bulb is at least three times that of a randomly chosen Longlive bulb.\\

\hfill \mbox{\textit{CAIE S2 2020 Q4 [10]}}