CAIE S2 2020 Specimen — Question 3 10 marks

Exam BoardCAIE
ModuleS2 (Statistics 2)
Year2020
SessionSpecimen
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPoisson distribution
TypeSingle time period probability
DifficultyModerate -0.5 This appears to be a standard Poisson distribution question asking about probability in a single time period with a given mean. Such questions typically involve direct application of the Poisson formula P(X=r) = e^(-λ)λ^r/r!, which is routine for S2 level with minimal problem-solving required beyond formula substitution and calculator work.
Spec5.02i Poisson distribution: random events model

3 The number of calls received at a small call centre has a Poisson distribution with mean 2.4 calls per 5-minute period.
  1. Find the probability of exactly 4 calls in an 8 -minute period.
  2. Find the probability of at least 3 calls in a 3-minute period.
    The number of calls received at a large call centre has a Poisson distribution with mean 41 calls per 5-minute period.
  3. Use an approximating distribution to find the probability that the number of calls received in a 5 -minute period is between 41 and 59 inclusive.

Question 3(a):
AnswerMarks Guidance
AnswerMarks Guidance
\(e^{-3.84} \times \dfrac{3.84^4}{4!}\)1, M1
\(= 0.195\) (3 sf)1, A1
Total: 2
Question 3(b):
AnswerMarks Guidance
AnswerMarks Guidance
\(1 - P(X = 0, 1, 2)\)1, M1 Attempted
\(1 - e^{-1.44}\left(1 + 1.44 + \dfrac{1.44^2}{2}\right)\)1, M1
\(= 0.176\)1, A1
Total: 3
Question 3(c):
AnswerMarks Guidance
AnswerMarks Guidance
\(X \sim N(41, 41)\)1, B1 Seen or implied
\(\dfrac{40.5 - 41}{\sqrt{41}}\) \((= -0.078)\) \(\dfrac{59.5 - 41}{\sqrt{41}}\) \((= 2.889)\)2, M1M1 M1 for each or M1M0 if no continuity correction (cc) or square root sign, or incorrect cc in both
\(\Phi(2.889') - \Phi(-0.078')\) \(= \Phi(2.889') - (1 - \Phi(0.078'))\) \(= 0.9981 - (1 - 0.5311)\)1, M1 Use of tables and correct area consistent with their working
\(= 0.529\) (3 sf)1, A1 Correct working only
Total: 5
## Question 3(a):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $e^{-3.84} \times \dfrac{3.84^4}{4!}$ | 1, M1 | |
| $= 0.195$ (3 sf) | 1, A1 | |
| **Total: 2** | | |

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## Question 3(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $1 - P(X = 0, 1, 2)$ | 1, M1 | Attempted |
| $1 - e^{-1.44}\left(1 + 1.44 + \dfrac{1.44^2}{2}\right)$ | 1, M1 | |
| $= 0.176$ | 1, A1 | |
| **Total: 3** | | |

---

## Question 3(c):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $X \sim N(41, 41)$ | 1, B1 | Seen or implied |
| $\dfrac{40.5 - 41}{\sqrt{41}}$ $(= -0.078)$ $\dfrac{59.5 - 41}{\sqrt{41}}$ $(= 2.889)$ | 2, M1M1 | M1 for each or M1M0 if no continuity correction (cc) or square root sign, or incorrect cc in both |
| $\Phi(2.889') - \Phi(-0.078')$ $= \Phi(2.889') - (1 - \Phi(0.078'))$ $= 0.9981 - (1 - 0.5311)$ | 1, M1 | Use of tables and correct area consistent with their working |
| $= 0.529$ (3 sf) | 1, A1 | Correct working only |
| **Total: 5** | | |

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3 The number of calls received at a small call centre has a Poisson distribution with mean 2.4 calls per 5-minute period.\\
(a) Find the probability of exactly 4 calls in an 8 -minute period.\\
(b) Find the probability of at least 3 calls in a 3-minute period.\\

The number of calls received at a large call centre has a Poisson distribution with mean 41 calls per 5-minute period.\\
(c) Use an approximating distribution to find the probability that the number of calls received in a 5 -minute period is between 41 and 59 inclusive.\\

\hfill \mbox{\textit{CAIE S2 2020 Q3 [10]}}