| Exam Board | OCR MEI |
|---|---|
| Module | Further Extra Pure (Further Extra Pure) |
| Year | 2021 |
| Session | November |
| Marks | 14 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | 3x3 Matrices |
| Type | Find P and D for diagonalization / matrix powers |
| Difficulty | Challenging +1.3 This is a Further Maths question on matrix diagonalization requiring finding characteristic equation, eigenvalues, eigenvectors, and expressing A^n using diagonalization. While systematic and multi-step (14 marks total), it follows a standard algorithmic procedure without requiring novel insight. The eigenvalues are given for verification, reducing computational burden. Harder than typical A-level due to Further Maths content and the A^n derivation, but still a textbook exercise. |
| Spec | 4.03h Determinant 2x2: calculation4.03n Inverse 2x2 matrix |
| Answer | Marks | Guidance |
|---|---|---|
| 3 | (a) | 3−λ 3 0 |
| Answer | Marks |
|---|---|
| = –λ3 + 9λ2 – 20λ + 12 = 0 | M1 |
| Answer | Marks |
|---|---|
| [3] | 1.1a |
| Answer | Marks |
|---|---|
| 1.1 | Formation of appropriate |
| Answer | Marks |
|---|---|
| Must be an equation. ISW. | May see eg expansion by 1st col: |
| Answer | Marks | Guidance |
|---|---|---|
| 3 | (b) | 1, 2 and 6 substituted into (a) equation to verify |
| [1] | 1.1 | eg checking trace is insufficient. |
| 3 | (c) | 3a + 3b = a or 2a or 6a |
| Answer | Marks |
|---|---|
| 1 0 2 | M1 |
| Answer | Marks |
|---|---|
| [4] | 1.1 |
| Answer | Marks |
|---|---|
| 1.1 | Correctly forming 3 equations in 3 |
| Answer | Marks |
|---|---|
| or any non-zero multiple. | Or formation of appropriate |
| Answer | Marks | Guidance |
|---|---|---|
| 3 | (d) | 3 −3 1 |
| Answer | Marks |
|---|---|
| | M1 |
| Answer | Marks |
|---|---|
| [6] | 3.1a |
| Answer | Marks |
|---|---|
| 1.1 | Forming matrix of their |
| Answer | Marks |
|---|---|
| Condone 6×6n unsimplified. | May be in decimal form: |
Question 3:
3 | (a) | 3−λ 3 0
det(A−λI)= 0 2−λ 2
1 3 4−λ
=(3−λ)[(2−λ)(4−λ)−2×3]−3(0−2×1) oe
= –λ3 + 9λ2 – 20λ + 12 = 0 | M1
M1
A1
[3] | 1.1a
1.1
1.1 | Formation of appropriate
determinant soi.
Attempt to expand determinant.
Allow one slip.
Must be an equation. ISW. | May see eg expansion by 1st col:
(3−λ)[(2−λ)(4−λ)−6]+1(6−0)
Or other formulation eg:
((3−λ)(2−λ)(4−λ)+6+0)
−(0+6(3−λ)+0)
3 | (b) | 1, 2 and 6 substituted into (a) equation to verify | B1
[1] | 1.1 | eg checking trace is insufficient.
3 | (c) | 3a + 3b = a or 2a or 6a
and 2b + 2c = b or 2b or 6b
and a + 3b + 4c = c or 2c or 6c
λ = 1: 2a = –3b, b = –2c
or λ = 2: c = 0, a = –3b
or λ = 6: a = b, c = 2b
3 −3 1
−2 or 1 or 1
1 0 2
3 −3 1
−2 and 1 and 1
1 0 2 | M1
M1
A1
A1
[4] | 1.1
1.1
1.1
1.1 | Correctly forming 3 equations in 3
unknowns for one of their
eigenvalues. May see explicit
choice of eg c = 1 to form 3
equations in 2 unknowns.
Attempt to solve equations for at
least one of their eigenvalues
leading to two unknowns in terms
of 3rd.
or any non-zero multiple.
or any non-zero multiple. | Or formation of appropriate
i j k
determinant eg −2 4−λ −4 .
0 −1 3−λ
Attempt to expand determinant
(might be in terms of λ) eg
8−7λ+λ2
6−2λ . Can be inferred by
2
2 correct coefficients.
3 | (d) | 3 −3 1
−2 1 1
1 0 2
−1
3 −3 1 −2 −6 4
1
−2 1 1 = −5 −5 5 oe
10
1 0 2 1 3 3
1 0 0 n 1 0 0
0 2 0 = 0 2n 0
0 0 6 0 0 6n
3 −3 11 0 0 −2 −6 4
−2 1 1 0 2n 0 1 −5 −5 5
10
1 0 2 0 0 6n 1 3 3
1 0 0 −2 −6 4
0 2n 0 −5 −5 5 =
0 0 6n 1 3 3
−2 −6 4
−5×2n −5×2n 5×2n
6n 3×6n 3×6n
3 −3 1 −2 −6 4
1
−2 1 1−5×2n −5×2n 5×2n=
10
1 0 2 6n 3×6n 3×6n
−6+15×2n+6n −18+15×2n+3×6n 12−15×2n+3×6n
1
4−5×2n+6n 12−5×2n+3×6n −8+5×2n+3×6n
10
−2+2×6n −6+6n+1 4+6n+1
| M1
A1FT
B1
M1
M1
A1
[6] | 3.1a
3.1a
3.1a
3.1a
1.1
1.1 | Forming matrix of their
eigenvectors, E.
BC. Finding inverse of their
matrix of eigenvectors.
Matrix of eigenvalues must be
consistent with matrix of
eigenvectors. Allow 1n.
Forming EΛnE–1. Can be awarded
if Λn incorrect or uncalculated but
eigenvectors must be in same
order as eigenvalues.
Proper attempt to multiply either
the first two or the last two (of 3)
in the correct order (with or
without 1 ).
10
or
3 −3×2n 6n −2 −6 4
1
−2 2n 6n −5 −5 5 =
10
1 0 2×6n 1 3 3
etc.
Condone 6×6n unsimplified. | May be in decimal form:
−0.2 −0.6 0.4
−0.5 −0.5 0.5
0.1 0.3 0.3
3 −3 11 0 0
−2 1 1 0 2n 0 =
1 0 2 0 0 6n
or
3 −3×2n 6n
−2 2n 6n
2×6n
1 0
The matrix $\mathbf{A}$ is given by $\mathbf{A} = \begin{pmatrix} 3 & 3 & 0 \\ 0 & 2 & 2 \\ 1 & 3 & 4 \end{pmatrix}$.
\begin{enumerate}[label=(\alph*)]
\item Determine the characteristic equation of $\mathbf{A}$. [3]
\item Hence verify that the eigenvalues of $\mathbf{A}$ are 1, 2 and 6. [1]
\item For each eigenvalue of $\mathbf{A}$ determine an associated eigenvector. [4]
\item Use the results of parts (b) and (c) to find $\mathbf{A}^n$ as a single matrix, where $n$ is a positive integer. [6]
\end{enumerate}
\hfill \mbox{\textit{OCR MEI Further Extra Pure 2021 Q3 [14]}}