AQA Further Paper 2 2019 June — Question 5 4 marks

Exam BoardAQA
ModuleFurther Paper 2 (Further Paper 2)
Year2019
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHyperbolic functions
TypeArc length with hyperbolic curves
DifficultyStandard +0.8 This is a standard arc length formula application requiring knowledge of hyperbolic function derivatives and the identity cosh²x - sinh²x = 1. While it involves Further Maths content (hyperbolic functions), the derivation is straightforward: differentiate cosh x to get sinh x, substitute into the arc length formula to get ∫√(1 + sinh²x)dx = ∫cosh x dx, which integrates directly to sinh x. The question is routine for Further Maths students who know the key identity, making it moderately above average difficulty on an absolute scale.
Spec1.08d Evaluate definite integrals: between limits4.07d Differentiate/integrate: hyperbolic functions

A curve has equation \(y = \cosh x\) Show that the arc length of the curve from \(x = a\) to \(x = b\), where \(0 < a < b\), is equal to $$\sinh b - \sinh a$$ [4 marks]

Question 5:
AnswerMarks
5Correctly substitutes the
derivative of in the
formula for arc length.
AnswerMarks Guidance
Condone miscsoinsgh 𝑎𝑎limits.AO1.2 M1
2 2
d𝑦𝑦
𝑠𝑠=��1+� � � d𝑎𝑎
𝑎𝑎 d𝑎𝑎
d𝑦𝑦
=sinh𝑎𝑎
d𝑎𝑎
2
d𝑦𝑦 2 2
1+� � = 1+sinh 𝑎𝑎 = cosh 𝑎𝑎
d𝑏𝑏𝑎𝑎 𝑏𝑏
1
2 2
𝑠𝑠 = �(cosh 𝑎𝑎) d𝑎𝑎 = � cosh𝑎𝑎d𝑎𝑎
𝑎𝑎 𝑎𝑎
𝑏𝑏
= [sinh𝑎𝑎]𝑎𝑎
= sinh𝑏𝑏−sinh𝑎𝑎
Correctly uses the
hyperbolic identity
to simpli2fy the integ2rand.
AnswerMarks Guidance
1Co+nsdionnhe 𝑎𝑎 = cosh 𝑎𝑎AO1.1a M1
Correctly in2tegrates cosh xAO1.1a M1
S√u1b+stistuintehs 𝑎𝑎lim=itcso asnhd𝑎𝑎 uses
a rigorous argument to
AnswerMarks Guidance
show the required resultAO2.1 R1
Total4
QMarking Instructions AO
Question 5:
5 | Correctly substitutes the
derivative of in the
formula for arc length.
Condone miscsoinsgh 𝑎𝑎limits. | AO1.2 | M1 | 𝑏𝑏 1
2 2
d𝑦𝑦
𝑠𝑠=��1+� � � d𝑎𝑎
𝑎𝑎 d𝑎𝑎
d𝑦𝑦
=sinh𝑎𝑎
d𝑎𝑎
2
d𝑦𝑦 2 2
1+� � = 1+sinh 𝑎𝑎 = cosh 𝑎𝑎
d𝑏𝑏𝑎𝑎 𝑏𝑏
1
2 2
𝑠𝑠 = �(cosh 𝑎𝑎) d𝑎𝑎 = � cosh𝑎𝑎d𝑎𝑎
𝑎𝑎 𝑎𝑎
𝑏𝑏
= [sinh𝑎𝑎]𝑎𝑎
= sinh𝑏𝑏−sinh𝑎𝑎
Correctly uses the
hyperbolic identity
to simpli2fy the integ2rand.
1Co+nsdionnhe 𝑎𝑎 = cosh 𝑎𝑎 | AO1.1a | M1
Correctly in2tegrates cosh x | AO1.1a | M1
S√u1b+stistuintehs 𝑎𝑎lim=itcso asnhd𝑎𝑎 uses
a rigorous argument to
show the required result | AO2.1 | R1
Total | 4
Q | Marking Instructions | AO | Marks | Typical Solution
A curve has equation $y = \cosh x$

Show that the arc length of the curve from $x = a$ to $x = b$, where $0 < a < b$, is equal to
$$\sinh b - \sinh a$$
[4 marks]

\hfill \mbox{\textit{AQA Further Paper 2 2019 Q5 [4]}}