AQA Further Paper 1 Specimen — Question 7 11 marks

Exam BoardAQA
ModuleFurther Paper 1 (Further Paper 1)
SessionSpecimen
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
Topic3x3 Matrices
TypeGeometric interpretation of systems
DifficultyChallenging +1.8 This is a sophisticated Further Maths question requiring understanding of when three planes don't meet at a unique point (determinant = 0), then distinguishing between two geometric configurations (sheaf vs three parallel/coincident planes) by checking rank conditions, and finally solving a dependent system. It demands conceptual understanding beyond routine calculation, multiple analytical steps, and geometric interpretation, placing it well above average difficulty but not at the extreme end of Further Maths questions.
Spec4.03s Consistent/inconsistent: systems of equations4.03t Plane intersection: geometric interpretation

Three planes have equations, $$x - y + kz = 3$$ $$kx - 3y + 5z = -1$$ $$x - 2y + 3z = -4$$ Where \(k\) is a real constant. The planes do not meet at a unique point.
  1. Find the possible values of \(k\) [3 marks]
  2. There are two possible geometric configurations of the given planes. Identify each possible configurations, stating the corresponding value of \(k\) Fully justify your answer. [5 marks]
  3. Given further that the equations of the planes form a consistent system, find the solution of the system of equations. [3 marks]

Question 7:

AnswerMarks
7(a)Uses an appropriate method for
finding the values of k ( for
example expanding appropriate
AnswerMarks Guidance
determinant)AO1.1a M1
k –3 5 =0
1 –2 3
–3 5 k 5 k –3
+ +k =0
–2 3 1 3 1 –2
1 +3k – 5 + k (–2k + 3)=0
−2k2 +6k −4=0
k2 −3k+2=0
(k−2)(k−1)=0
k = 2 or 1
AnswerMarks Guidance
Obtains a quadratic equation in kAO1.1a M1
Obtains two correct values for kAO1.1b A1
(b)Selects an appropriate method to
determine the appropriate
geometrical configuration and
AnswerMarks Guidance
substitutes ‘their’ first value of kAO3.1a M1
x− y + z =3
x−3y+5z = −1
x−2y+3z = −4
−2y+4z =−4
y−2z =7
y−2z =2; y−2z =7
Hence equations are inconsistent and the
three planes form a prism
when k = 2
x− y+2z =3
2x−3y+5z =−1
x−2y+3z =−4
R −2R :−y+z =−7
2 1
R −R :−y+z =−7
3 1
Hence equations are consistent and the
three planes form a sheaf – they meet in
line
Eliminates one variable or uses
AnswerMarks Guidance
row reductionAO1.1a M1
Obtains a contradiction and
makes correct deduction about
the geometric configuration
AnswerMarks Guidance
(must have correct value for k)AO2.2a R1
Substitutes ‘their’ 2nd value of k
into selected method to determine
the appropriate geometrical
AnswerMarks Guidance
configurationAO1.1a M1
Obtains a consistent set of
equations and makes correct
deduction about geometric
configuration (must have correct
AnswerMarks Guidance
value for k)AO2.2a R1
QMarking Instructions AO
(c)Deduces that the planes must
meet in a line and hence that
AnswerMarks Guidance
k = 2AO2.2a R1
2x−3y+5z =−1
x−2y+3z =−4
⇒−y+z =−7
Let
z =λ
Then
y =λ+7
and
x =3+ y−2z
=3+λ+7−2λ
=−λ+10
Selects method to find
solution: For example, sets
one variable = λ, substitutes
and attempts to find other
AnswerMarks Guidance
variables in terms of λAO1.1a M1
 1   1   1 
     
−1 × −2 = −1
     
     
 2   3  −1
x 10  1 
     
y = 7 +λ −1
     
     
AnswerMarks
z  0  −1 1   1   1 
     
−1 × −2 = −1
     
     
 2   3  −1
x 10  1 
     
y = 7 +λ −1
     
     
z  0  −1
Fully states correct solution
AnswerMarks Guidance
CAOAO1.1b A1
Total11
QMarking Instructions AO
Question 7:
--- 7(a) ---
7(a) | Uses an appropriate method for
finding the values of k ( for
example expanding appropriate
determinant) | AO1.1a | M1 | 1 –1 k
k –3 5 =0
1 –2 3
–3 5 k 5 k –3
+ +k =0
–2 3 1 3 1 –2
1 +3k – 5 + k (–2k + 3)=0
−2k2 +6k −4=0
k2 −3k+2=0
(k−2)(k−1)=0
k = 2 or 1
Obtains a quadratic equation in k | AO1.1a | M1
Obtains two correct values for k | AO1.1b | A1
(b) | Selects an appropriate method to
determine the appropriate
geometrical configuration and
substitutes ‘their’ first value of k | AO3.1a | M1 | when k =1
x− y + z =3
x−3y+5z = −1
x−2y+3z = −4
−2y+4z =−4
y−2z =7
y−2z =2; y−2z =7
Hence equations are inconsistent and the
three planes form a prism
when k = 2
x− y+2z =3
2x−3y+5z =−1
x−2y+3z =−4
R −2R :−y+z =−7
2 1
R −R :−y+z =−7
3 1
Hence equations are consistent and the
three planes form a sheaf – they meet in
line
Eliminates one variable or uses
row reduction | AO1.1a | M1
Obtains a contradiction and
makes correct deduction about
the geometric configuration
(must have correct value for k) | AO2.2a | R1
Substitutes ‘their’ 2nd value of k
into selected method to determine
the appropriate geometrical
configuration | AO1.1a | M1
Obtains a consistent set of
equations and makes correct
deduction about geometric
configuration (must have correct
value for k) | AO2.2a | R1
Q | Marking Instructions | AO | Marks | Typical Solution
(c) | Deduces that the planes must
meet in a line and hence that
k = 2 | AO2.2a | R1 | x− y+2z =3
2x−3y+5z =−1
x−2y+3z =−4
⇒−y+z =−7
Let
z =λ
Then
y =λ+7
and
x =3+ y−2z
=3+λ+7−2λ
=−λ+10
Selects method to find
solution: For example, sets
one variable = λ, substitutes
and attempts to find other
variables in terms of λ | AO1.1a | M1 | ALT
 1   1   1 
     
−1 × −2 = −1
     
     
 2   3  −1
x 10  1 
     
y = 7 +λ −1
     
     
z  0  −1 |  1   1   1 
     
−1 × −2 = −1
     
     
 2   3  −1
x 10  1 
     
y = 7 +λ −1
     
     
z  0  −1
Fully states correct solution
CAO | AO1.1b | A1
Total | 11
Q | Marking Instructions | AO | Marks | Typical Solution
Three planes have equations,
$$x - y + kz = 3$$
$$kx - 3y + 5z = -1$$
$$x - 2y + 3z = -4$$

Where $k$ is a real constant. The planes do not meet at a unique point.

\begin{enumerate}[label=(\alph*)]
\item Find the possible values of $k$
[3 marks]

\item There are two possible geometric configurations of the given planes.

Identify each possible configurations, stating the corresponding value of $k$

Fully justify your answer.
[5 marks]

\item Given further that the equations of the planes form a consistent system, find the solution of the system of equations.
[3 marks]
\end{enumerate}

\hfill \mbox{\textit{AQA Further Paper 1  Q7 [11]}}