AQA Further Paper 1 2024 June — Question 1 1 marks

Exam BoardAQA
ModuleFurther Paper 1 (Further Paper 1)
Year2024
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicRoots of polynomials
TypeSymmetric functions of roots
DifficultyEasy -1.2 This is a direct application of Vieta's formulas requiring only recall of the standard result that for ax³+bx²+cx+d=0, the sum of products of roots taken two at a time equals c/a. Here, αβ+βγ+γα = -4/20 = -1/5. It's a 1-mark multiple-choice question testing basic knowledge with no problem-solving or manipulation required, making it easier than average even for Further Maths.
Spec4.05a Roots and coefficients: symmetric functions

The roots of the equation \(20x^3 - 16x^2 - 4x + 7 = 0\) are \(\alpha\), \(\beta\) and \(\gamma\) Find the value of \(\alpha\beta + \beta\gamma + \gamma\alpha\) Circle your answer. [1 mark] \(-\frac{4}{5}\) \(-\frac{1}{5}\) \(\frac{1}{5}\) \(\frac{4}{5}\)

Question 1:
AnswerMarks Guidance
1Circles 2nd answer 1.1b
5
AnswerMarks Guidance
Question total1
QMarking instructions AO
Question 1:
1 | Circles 2nd answer | 1.1b | B1 | 1
–
5
Question total | 1
Q | Marking instructions | AO | Marks | Typical solution
The roots of the equation $20x^3 - 16x^2 - 4x + 7 = 0$ are $\alpha$, $\beta$ and $\gamma$

Find the value of $\alpha\beta + \beta\gamma + \gamma\alpha$

Circle your answer.
[1 mark]

$-\frac{4}{5}$ $-\frac{1}{5}$ $\frac{1}{5}$ $\frac{4}{5}$

\hfill \mbox{\textit{AQA Further Paper 1 2024 Q1 [1]}}