AQA Further Paper 1 2023 June — Question 15 9 marks

Exam BoardAQA
ModuleFurther Paper 1 (Further Paper 1)
Year2023
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSecond order differential equations
TypeCombined polynomial and trigonometric RHS
DifficultyChallenging +1.2 This is a standard second-order linear ODE with constant coefficients requiring both complementary function (solving auxiliary equation m² - 3m - 4 = 0) and particular integral (trying y = A cos 2x + B sin 2x + Cx + D). While it involves multiple steps and careful algebra, it follows a completely routine procedure taught in Further Maths with no novel problem-solving required. The 9 marks reflect length rather than conceptual difficulty, making it moderately above average but well within standard Further Maths territory.
Spec4.10d Second order homogeneous: auxiliary equation method4.10e Second order non-homogeneous: complementary + particular integral

Find the general solution of the differential equation $$\frac{\mathrm{d}^2y}{\mathrm{d}x^2} - 3\frac{\mathrm{d}y}{\mathrm{d}x} - 4y = \cos 2x + 5x$$ [9 marks]

Question 15:
AnswerMarks Guidance
15Uses auxiliary equation 3.1a
CF: 2
PI: y = pcos2− 𝑚𝑚x𝑥𝑥+−qs3i𝑚𝑚 4n𝑥𝑥2−x4+=rx0+⇒s𝑚𝑚 =4,−1
𝑦𝑦=𝐴𝐴𝑒𝑒 +𝐵𝐵𝑒𝑒
y'=−2psin2x+2qcos2x+r
y''=−4pcos2x−4qsin2x
−4pcos2x−4qsin2x+6psin2x−6qcos2x−3r
−4pcos2x−4qsin2x−4rx−4s=cos2x+5x
6p−8q=0
−6q−8p=1
3 2
𝑞𝑞 =− ,𝑝𝑝=−
−4r=55⇒0 r=−52 5
4
−3r−4s=0⇒s=15
16
y= Ae−x +Be4x − 2 cos2x− 3 sin2x−5 x+15
25 50 4 16
Obtains correct
AnswerMarks Guidance
complementary function1.1b A1
Uses correct form of
AnswerMarks Guidance
particular integral3.1a M1
Obtains first and second
derivatives of their
AnswerMarks Guidance
particular integral1.1a M1
Substitutes first and
second derivatives of
AnswerMarks Guidance
particular integral into DE3.1a M1
Forms a pair of
simultaneous equations
by comparing
coefficients of cos2xand
AnswerMarks Guidance
sin2x and solves them3.1a M1
Forms a pair of
simultaneous equations
by comparing coefficient
of xand constant term
AnswerMarks Guidance
and solves them3.1a M1
Obtains correct trig
constants or linear
AnswerMarks Guidance
constants1.1b A1
Completes a reasoned
argument to obtain
completely correct
AnswerMarks Guidance
solution, including y =2.1 R1
Total9
QMarking instructions AO
Question 15:
15 | Uses auxiliary equation | 3.1a | M1 | aux. equation
CF: 2
PI: y = pcos2− 𝑚𝑚x𝑥𝑥+−qs3i𝑚𝑚 4n𝑥𝑥2−x4+=rx0+⇒s𝑚𝑚 =4,−1
𝑦𝑦=𝐴𝐴𝑒𝑒 +𝐵𝐵𝑒𝑒
y'=−2psin2x+2qcos2x+r
y''=−4pcos2x−4qsin2x
−4pcos2x−4qsin2x+6psin2x−6qcos2x−3r
−4pcos2x−4qsin2x−4rx−4s=cos2x+5x
6p−8q=0
−6q−8p=1
3 2
𝑞𝑞 =− ,𝑝𝑝=−
−4r=55⇒0 r=−52 5
4
−3r−4s=0⇒s=15
16
y= Ae−x +Be4x − 2 cos2x− 3 sin2x−5 x+15
25 50 4 16
Obtains correct
complementary function | 1.1b | A1
Uses correct form of
particular integral | 3.1a | M1
Obtains first and second
derivatives of their
particular integral | 1.1a | M1
Substitutes first and
second derivatives of
particular integral into DE | 3.1a | M1
Forms a pair of
simultaneous equations
by comparing
coefficients of cos2xand
sin2x and solves them | 3.1a | M1
Forms a pair of
simultaneous equations
by comparing coefficient
of xand constant term
and solves them | 3.1a | M1
Obtains correct trig
constants or linear
constants | 1.1b | A1
Completes a reasoned
argument to obtain
completely correct
solution, including y = | 2.1 | R1
Total | 9
Q | Marking instructions | AO | Marks | Typical solution
Find the general solution of the differential equation
$$\frac{\mathrm{d}^2y}{\mathrm{d}x^2} - 3\frac{\mathrm{d}y}{\mathrm{d}x} - 4y = \cos 2x + 5x$$
[9 marks]

\hfill \mbox{\textit{AQA Further Paper 1 2023 Q15 [9]}}