AQA Further Paper 1 2023 June — Question 4 1 marks

Exam BoardAQA
ModuleFurther Paper 1 (Further Paper 1)
Year2023
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSecond order differential equations
TypeSketch or describe solution behavior
DifficultyStandard +0.3 This is a conceptual recognition question about damping types in differential equations. Students need to recall that heavy damping corresponds to two distinct real negative roots (no oscillation), making the third option correct. While it requires understanding of damping classifications, it's a single-mark multiple-choice question testing standard theory without calculation, making it slightly easier than average.
Spec4.10g Damped oscillations: model and interpret

The solution of a second order differential equation is \(f(t)\) The differential equation models heavy damping. Which one of the statements below could be true? Tick \((\checkmark)\) one box. [1 mark] \(f(t) = 2\mathrm{e}^{-t} \cos(3t) + 5\mathrm{e}^{-t} \sin(3t) \quad \square\) \(f(t) = 3\mathrm{e}^{-t} + 4t\mathrm{e}^{-t} \quad \square\) \(f(t) = 7\mathrm{e}^{-t} + 2\mathrm{e}^{-2t} \quad \square\) \(f(t) = 8\mathrm{e}^{-t} \cos(3t - 0.1) \quad \square\)

Question 4:
AnswerMarks Guidance
4Ticks correct answer 1.2
Total1
QMarking instructions AO
Question 4:
4 | Ticks correct answer | 1.2 | B1 | f(t) =7e−t +2e−2t
Total | 1
Q | Marking instructions | AO | Marks | Typical solution
The solution of a second order differential equation is $f(t)$

The differential equation models heavy damping.

Which one of the statements below could be true?

Tick $(\checkmark)$ one box.
[1 mark]

$f(t) = 2\mathrm{e}^{-t} \cos(3t) + 5\mathrm{e}^{-t} \sin(3t) \quad \square$

$f(t) = 3\mathrm{e}^{-t} + 4t\mathrm{e}^{-t} \quad \square$

$f(t) = 7\mathrm{e}^{-t} + 2\mathrm{e}^{-2t} \quad \square$

$f(t) = 8\mathrm{e}^{-t} \cos(3t - 0.1) \quad \square$

\hfill \mbox{\textit{AQA Further Paper 1 2023 Q4 [1]}}