AQA Paper 3 2019 June — Question 1 1 marks

Exam BoardAQA
ModulePaper 3 (Paper 3)
Year2019
SessionJune
Marks1
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Mark schemeDownload PDF ↗
TopicComplex Numbers Argand & Loci
TypeModulus-argument form conversion
DifficultyEasy -2.0 This is a 1-mark multiple-choice question requiring only direct recall of the domain of arcsin x, with no calculation or problem-solving involved. It tests basic knowledge that arcsin is defined for inputs between -1 and 1, which is standard A-level content requiring minimal thought.
Spec1.05i Inverse trig functions: arcsin, arccos, arctan domains and graphs
\(f(x) = \arcsin x\) State the maximum possible domain of \(f\) Tick \((\checkmark)\) one box. [1 mark] \(\{x \in \mathbb{R} : -1 \leq x \leq 1\}\) \(\left\{x \in \mathbb{R} : -\frac{\pi}{2} \leq x \leq \frac{\pi}{2}\right\}\) \(\{x \in \mathbb{R} : -\pi \leq x \leq \pi\}\) \(\{x \in \mathbb{R} : -90 \leq x \leq 90\}\)
Question 1:
AnswerMarks Guidance
1Ticks the correct response 1.2
Total1
QMarking instructions AO 
Question 1:
1 | Ticks the correct response | 1.2 | B1
Total | 1
Q | Marking instructions | AO | Mark | Typical solution
$f(x) = \arcsin x$

State the maximum possible domain of $f$

Tick $(\checkmark)$ one box.
[1 mark]

$\{x \in \mathbb{R} : -1 \leq x \leq 1\}$

$\left\{x \in \mathbb{R} : -\frac{\pi}{2} \leq x \leq \frac{\pi}{2}\right\}$

$\{x \in \mathbb{R} : -\pi \leq x \leq \pi\}$

$\{x \in \mathbb{R} : -90 \leq x \leq 90\}$

\hfill \mbox{\textit{AQA Paper 3 2019 Q1 [1]}}
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Q1 1 Q2 1 Q3 1 Q4 3 Q5 5 Q6 4 Q7 8 Q8 12 Q9 15 Q10 1 Q11 1 Q12 6 Q13 10 Q14 7 Q15 3 Q16 10 Q17 12