| Exam Board | AQA |
|---|---|
| Module | Paper 3 (Paper 3) |
| Year | 2018 |
| Session | June |
| Marks | 12 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Hypothesis test of binomial distributions |
| Type | Two-tailed test critical region |
| Difficulty | Standard +0.3 This is a standard two-tailed and one-tailed binomial hypothesis test at A-level. Part (a) requires setting up hypotheses, calculating binomial probabilities, and comparing to significance level. Part (b) requires finding a critical value for a one-tailed test. Both are routine applications of S1/S2 content with no novel insight required, making it slightly easier than average. |
| Spec | 2.05b Hypothesis test for binomial proportion2.05c Significance levels: one-tail and two-tail |
| Answer | Marks | Guidance |
|---|---|---|
| 17 (a) | States both hypotheses correctly for | |
| two-tailed test | AO2.5 | B1 |
| Answer | Marks | Guidance |
|---|---|---|
| States model used PI | AO3.3 | M1 |
| Answer | Marks | Guidance |
|---|---|---|
| 0.828(1) or 0.945(3) | AO1.1a | M1 |
| Obtains the correct probability for | AO1.1b | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| with 0.05 | AO3.5a | M1 |
| Answer | Marks | Guidance |
|---|---|---|
| ππ(ππ β₯ 70) | AO2.2b | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| and B1 scored) | AO3.2a | E1F |
| Answer | Marks |
|---|---|
| 17(a) | (ALTERNATIVE using critical region) |
| Answer | Marks | Guidance |
|---|---|---|
| two-tailed test | AO2.5 | B1 |
| Answer | Marks | Guidance |
|---|---|---|
| States model used PI | AO3.3 | M1 |
| Considers critical region | AO1.1a | M1 |
| Identifies critical region | AO1.1b | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| with critical values | AO3.5a | M1 |
| Answer | Marks | Guidance |
|---|---|---|
| ππ = 7 0 | AO2.2b | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| required. | AO3.2a | E1F |
| Q | Marking Instructions | AO |
| Answer | Marks | Guidance |
|---|---|---|
| 17(b) | States model used PI | AO3.3 |
| Answer | Marks | Guidance |
|---|---|---|
| sight of | AO3.1b | M1 |
| Answer | Marks | Guidance |
|---|---|---|
| ππ(ππ β₯ ππ) < 0.1 | AO3.2b | R1 |
| Answer | Marks | Guidance |
|---|---|---|
| probabilities | AO1.1b | A1 |
| Answer | Marks | Guidance |
|---|---|---|
| matches CSO | AO3.2a | A1 |
| Total | 12 | |
| Marking Instructions | AO | Marks |
Question 17:
--- 17 (a) ---
17 (a) | States both hypotheses correctly for
two-tailed test | AO2.5 | B1 | X = number of matches won
H : p = 0.5
0
H : p β 0.5
1
Under null hypothesis
XβΌB(10,0.5)
ππ(ππ β₯ 7)= 1βππ(ππ β€ 6)
= 1β0.8281
= 0.172
0.172> 0.05
Accept H
0
There is not sufficient evidence
that Suzanneβs new racket has
made a difference
States model used PI | AO3.3 | M1
Calculates or
ππ(ππ β€ 6) ππ(ππ β€ 7)
0.828(1) or 0.945(3) | AO1.1a | M1
Obtains the correct probability for | AO1.1b | A1
Evaluates Binomial model by comparing
ππ(ππ β₯ 7)
with 0.05 | AO3.5a | M1
Infers H accepted CSO
ππ(ππ β₯ 70) | AO2.2b | A1
Concludes correctly in context. (FT only
available if previous M1 mark scored
and B1 scored) | AO3.2a | E1F
--- 17(a) ---
17(a) | (ALTERNATIVE using critical region)
States both hypotheses correctly for
two-tailed test | AO2.5 | B1 | X = number of matches won
H : p=0.5
0
H : pβ 0.5
1
Under null hypothesis
XβΌB(10,0.5)
ππ(ππ β€ 1)= 0.0107 ππππ 0.0108
ππ(ππ β₯ 9)= 0.0107 ππππ 0.0108
Critical region is
and
not in critical region
ππ β€ 1 ππ β₯ 9
ππ = 7
Accept H
0
There is not sufficient evidence
that Suzanneβs new racket has
made a difference
States model used PI | AO3.3 | M1
Considers critical region | AO1.1a | M1
Identifies critical region | AO1.1b | A1
Evaluates Binomial model by comparing
with critical values | AO3.5a | M1
Infers H accepted CSO
ππ = 7 0 | AO2.2b | A1
Correctly concludes in context. βNot
sufficient evidenceβ or equivalent
required. | AO3.2a | E1F
Q | Marking Instructions | AO | Marks | Typical Solution
--- 17(b) ---
17(b) | States model used PI | AO3.3 | M1 | YβΌB(20,0.5)
Require P(Y > y)<0.1
P ( Y β₯13 )=0.1316>0.1
P ( Y β₯14 )=0.0577>0.1
Minimum number of matches
= 14
Expresses condition in terms of a
cumulative probability statement PI by
sight of | AO3.1b | M1
Tests one appropriate value for y
ππ(ππ β₯ ππ) < 0.1 | AO3.2b | R1
Obtains at least two correct cumulative
probabilities | AO1.1b | A1
Obtains the correct minimum number of
matches CSO | AO3.2a | A1
Total | 12
Marking Instructions | AO | Marks | Typical Solution
Suzanne is a member of a sports club.
For each sport she competes in, she wins half of the matches.
\begin{enumerate}[label=(\alph*)]
\item After buying a new tennis racket Suzanne plays 10 matches and wins 7 of them.
Investigate, at the 10% level of significance, whether Suzanne's new racket has made a difference to the probability of her winning a match.
[7 marks]
\item After buying a new squash racket, Suzanne plays 20 matches. Find the minimum number of matches she must win for her to conclude, at the 10% level of significance, that the new racket has improved her performance.
[5 marks]
\end{enumerate}
\hfill \mbox{\textit{AQA Paper 3 2018 Q17 [12]}}