AQA Paper 3 2018 June — Question 3 1 marks

Exam BoardAQA
ModulePaper 3 (Paper 3)
Year2018
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStraight Lines & Coordinate Geometry
TypePerpendicular line through point
DifficultyEasy -1.8 This is a 1-mark multiple choice question testing basic recall of perpendicular line properties. Students only need to know that perpendicular lines have gradients m₁ and m₂ where m₁m₂ = -1, or equivalently that coefficients swap and one changes sign (2x + 3y becomes 3x - 2y). No calculation or problem-solving required—pure pattern recognition.
Spec1.03a Straight lines: equation forms y=mx+c, ax+by+c=01.03b Straight lines: parallel and perpendicular relationships

The line \(L\) has equation \(2x + 3y = 7\) Which one of the following is perpendicular to \(L\)? Tick one box. [1 mark] \(2x - 3y = 7\) \(3x + 2y = -7\) \(2x + 3y = -\frac{1}{7}\) \(3x - 2y = 7\)

Question 3:
AnswerMarks Guidance
3Circles correct answer AO1.1b
Total1
QMarking Instructions AO
Question 3:
3 | Circles correct answer | AO1.1b | B1 | 3x−2y =7
Total | 1
Q | Marking Instructions | AO | Marks | Typical Solution
The line $L$ has equation $2x + 3y = 7$

Which one of the following is perpendicular to $L$?

Tick one box.
[1 mark]

$2x - 3y = 7$

$3x + 2y = -7$

$2x + 3y = -\frac{1}{7}$

$3x - 2y = 7$

\hfill \mbox{\textit{AQA Paper 3 2018 Q3 [1]}}