| Exam Board | AQA |
|---|---|
| Module | AS Paper 1 (AS Paper 1) |
| Session | Specimen |
| Marks | 2 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Vectors Introduction & 2D |
| Type | Unit vector in given direction |
| Difficulty | Easy -1.2 This is a straightforward two-part question on basic 2D vectors requiring only direct application of the magnitude formula (√((-20)² + 21²) = 29) and recognition that the vector points in the second quadrant (negative i-component, positive j-component means 90° < θ < 180°). Both parts are single-mark multiple choice with minimal calculation, making this easier than average A-level content. |
| Spec | 1.10a Vectors in 2D: i,j notation and column vectors1.10c Magnitude and direction: of vectors |
| Answer | Marks | Guidance |
|---|---|---|
| 13(a) | Circles correct answer | AO1.1b |
| (b) | Circles correct answer | AO2.2a |
| Total | 2 |
Question 13:
--- 13(a) ---
13(a) | Circles correct answer | AO1.1b | B1 | 29
(b) | Circles correct answer | AO2.2a | B1 | 90º < θ < 135º
Total | 2\begin{enumerate}[label=(\alph*)]
\item The unit vectors $\mathbf{i}$ and $\mathbf{j}$ are perpendicular.
Find the magnitude of the vector $-20\mathbf{i} + 21\mathbf{j}$
Circle your answer.
[1 mark]
$-1$ $1$ $\sqrt{41}$ $29$
\item The angle between the vector $\mathbf{i}$ and the vector $-20\mathbf{i} + 21\mathbf{j}$ is $\theta$
Which statement about $\theta$ is true?
Circle your answer.
[1 mark]
$0° < \theta < 45°$ $45° < \theta < 90°$ $90° < \theta < 135°$ $135° < \theta < 180°$
\end{enumerate}
\hfill \mbox{\textit{AQA AS Paper 1 Q13 [2]}}