AQA AS Paper 1 Specimen — Question 8 6 marks

Exam BoardAQA
ModuleAS Paper 1 (AS Paper 1)
SessionSpecimen
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Theorem (positive integer n)
TypeNumerical approximation using expansion
DifficultyModerate -0.8 Part (a) is direct application of the binomial expansion formula requiring only substitution and basic arithmetic. Part (b) requires recognizing that 0.998 = 1 - 2(0.001) and evaluating the approximation, which is a standard textbook application. The question tests routine binomial expansion skills with minimal problem-solving, making it easier than average for A-level.
Spec1.04a Binomial expansion: (a+b)^n for positive integer n

  1. Find the first three terms, in ascending powers of \(x\), of the expansion of \((1 - 2x)^{10}\) [3 marks]
  2. Carly has lost her calculator. She uses the first three terms, in ascending powers of \(x\), of the expansion of \((1 - 2x)^{10}\) to evaluate \(0.998^{10}\) Find Carly's value for \(0.998^{10}\) and show that it is correct to five decimal places. [3 marks]

Question 8:

AnswerMarks
8(a)Uses binomial theorem to expand
bracket – correct unsimplified
AnswerMarks Guidance
expression but condone sign errorAO1.1a M1
1 (2x)1 (2x)2
   
 1   2 
120x180x2...
Obtains constant term and x term,
AnswerMarks Guidance
both correctAO1.1b A1
Obtains correct x2 termAO1.1b A1
(b)Selects x = 0.001 AO3.1a
1 – 0.020 + 0.000180 = 0.98018
0.99810 = 0.980179… = 0.98018 to 5
dp, which matches Carly’s value.
Substitutes ‘their’ chosen value of x
into ‘their’ expansion from part (a) to
AnswerMarks Guidance
obtain a 5 decimal place valueAO1.1a M1
Gives a correct explanation to confirm
that the value found from the
calculator is 0.98018 to 5 decimal
places which is the same as the value
AnswerMarks Guidance
found by using the expansionAO2.4 A1
Total6
QMarking Instructions AO
Question 8:
--- 8(a) ---
8(a) | Uses binomial theorem to expand
bracket – correct unsimplified
expression but condone sign error | AO1.1a | M1 | 10 10
1 (2x)1 (2x)2
   
 1   2 
120x180x2...
Obtains constant term and x term,
both correct | AO1.1b | A1
Obtains correct x2 term | AO1.1b | A1
(b) | Selects x = 0.001 | AO3.1a | B1 | Substituting x = 0.001
1 – 0.020 + 0.000180 = 0.98018
0.99810 = 0.980179… = 0.98018 to 5
dp, which matches Carly’s value.
Substitutes ‘their’ chosen value of x
into ‘their’ expansion from part (a) to
obtain a 5 decimal place value | AO1.1a | M1
Gives a correct explanation to confirm
that the value found from the
calculator is 0.98018 to 5 decimal
places which is the same as the value
found by using the expansion | AO2.4 | A1
Total | 6
Q | Marking Instructions | AO | Marks | Typical Solution
\begin{enumerate}[label=(\alph*)]
\item Find the first three terms, in ascending powers of $x$, of the expansion of $(1 - 2x)^{10}$ [3 marks]

\item Carly has lost her calculator. She uses the first three terms, in ascending powers of $x$, of the expansion of $(1 - 2x)^{10}$ to evaluate $0.998^{10}$

Find Carly's value for $0.998^{10}$ and show that it is correct to five decimal places.
[3 marks]
\end{enumerate}

\hfill \mbox{\textit{AQA AS Paper 1  Q8 [6]}}