AQA AS Paper 1 2024 June — Question 16 3 marks

Exam BoardAQA
ModuleAS Paper 1 (AS Paper 1)
Year2024
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSUVAT in 2D & Gravity
TypeVertical projection: speed of projection
DifficultyEasy -1.2 This is a straightforward mechanics question requiring direct application of a single SUVAT equation (v² = u² + 2as) with clearly stated values. It's a standard AS-level kinematics problem with no problem-solving required beyond selecting and applying the appropriate equation, making it easier than average.
Spec3.02d Constant acceleration: SUVAT formulae3.02h Motion under gravity: vector form

In this question use \(g = 9.8\) m s\(^{-2}\) A ball is launched vertically upwards from the Earth's surface with velocity \(u\) m s\(^{-1}\) The ball reaches a maximum height of 15 metres. You may assume that air resistance can be ignored. Find the value of \(u\) [3 marks]

Question 16:
AnswerMarks Guidance
16Uses v2 =u2 +2as
Condone sign errors3.4 M1
0=u2 +2(−9.8)(15)
u =17
Substitutes consistent values to
find u
eg a=−9.8,v=0,s=15
AnswerMarks Guidance
a=9.8,v=0,s=−153.3 A1
Obtains u =17 CSO
AnswerMarks Guidance
AWRT 17 ACF1.1b A1
Question 16 Total3
QMarking instructions AO
Question 16:
16 | Uses v2 =u2 +2as
Condone sign errors | 3.4 | M1 | a=−9.8,v=0,s=15
0=u2 +2(−9.8)(15)
u =17
Substitutes consistent values to
find u
eg a=−9.8,v=0,s=15
a=9.8,v=0,s=−15 | 3.3 | A1
Obtains u =17 CSO
AWRT 17 ACF | 1.1b | A1
Question 16 Total | 3
Q | Marking instructions | AO | Marks | Typical solution
In this question use $g = 9.8$ m s$^{-2}$

A ball is launched vertically upwards from the Earth's surface with velocity $u$ m s$^{-1}$

The ball reaches a maximum height of 15 metres.

You may assume that air resistance can be ignored.

Find the value of $u$
[3 marks]

\hfill \mbox{\textit{AQA AS Paper 1 2024 Q16 [3]}}