AQA AS Paper 1 2024 June — Question 13 1 marks

Exam BoardAQA
ModuleAS Paper 1 (AS Paper 1)
Year2024
SessionJune
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicConstant acceleration (SUVAT)
DifficultyEasy -1.8 This is a 1-mark question requiring only direct recognition that acceleration is the coefficient of t in a linear velocity-time equation (v = u + at). It's pure recall with no calculation or problem-solving, making it significantly easier than average A-level questions.
Spec3.02a Kinematics language: position, displacement, velocity, acceleration3.02d Constant acceleration: SUVAT formulae

A particle is moving in a straight line with constant acceleration \(a\) m s\(^{-2}\) The particle's velocity, \(v\) m s\(^{-1}\), varies with time, \(t\) seconds, so that $$v = 3 - 4t$$ Deduce the value of \(a\) Circle your answer. [1 mark] \(-4\) \qquad \(-1\) \qquad \(3\) \qquad \(4\)

Question 13:
AnswerMarks Guidance
13Circles first answer 2.2a
Question 13 Total1
QMarking instructions AO
Question 13:
13 | Circles first answer | 2.2a | B1 | –4
Question 13 Total | 1
Q | Marking instructions | AO | Marks | Typical solution
A particle is moving in a straight line with constant acceleration $a$ m s$^{-2}$

The particle's velocity, $v$ m s$^{-1}$, varies with time, $t$ seconds, so that
$$v = 3 - 4t$$

Deduce the value of $a$

Circle your answer.
[1 mark]

$-4$ \qquad $-1$ \qquad $3$ \qquad $4$

\hfill \mbox{\textit{AQA AS Paper 1 2024 Q13 [1]}}