AQA AS Paper 1 2024 June — Question 11 5 marks

Exam BoardAQA
ModuleAS Paper 1 (AS Paper 1)
Year2024
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStationary points and optimisation
TypeClassify nature of stationary points
DifficultyStandard +0.3 This question requires integration of g''(x) to find g'(x), then using given conditions to find the constant. Students must evaluate g''(1) and g''(4) to classify turning points (straightforward second derivative test), then solve g'(x) > 0 for part (b). While it involves multiple steps and integration, these are standard AS-level techniques with no novel insight required—slightly easier than average due to the structured guidance.
Spec1.07e Second derivative: as rate of change of gradient1.07n Stationary points: find maxima, minima using derivatives1.07o Increasing/decreasing: functions using sign of dy/dx

It is given that for the continuous function \(g\) • \(g'(1) = 0\) • \(g'(4) = 0\) • \(g''(x) = 2x - 5\)
  1. Determine the nature of each of the turning points of \(g\) Fully justify your answer. [3 marks]
  2. Find the set of values of \(x\) for which \(g\) is an increasing function. [2 marks]

Question 11:

AnswerMarks Guidance
11(a)Evaluates g′′(1) or g′′(4) 3.1a
–3 < 0 therefore maximum at x = 1
g′′(4) = 3
3 > 0 therefore minimum at x = 4
Deduces nature of the turning
point at x = 1 or the turning point
AnswerMarks Guidance
at x = 42.2a A1
Obtains g′′(1) = –3 and
g′′(4) = 3 and compares each
value with 0 to correctly deduce
the nature of both turning points
Must link to explicitly stated x
values or coordinates
Condone incorrect y values for
AnswerMarks Guidance
any coordinates given2.2a R1
Subtotal3
QMarking instructions AO

AnswerMarks Guidance
11(b)Identifies one correct increasing
region2.4 M1
Obtains x < 1, x > 4
AnswerMarks Guidance
Accept x≤1, x≥42.1 R1
Subtotal2
Question 11 Total5
QMarking instructions AO
Question 11:
--- 11(a) ---
11(a) | Evaluates g′′(1) or g′′(4) | 3.1a | M1 | g′′(1) = –3
–3 < 0 therefore maximum at x = 1
g′′(4) = 3
3 > 0 therefore minimum at x = 4
Deduces nature of the turning
point at x = 1 or the turning point
at x = 4 | 2.2a | A1
Obtains g′′(1) = –3 and
g′′(4) = 3 and compares each
value with 0 to correctly deduce
the nature of both turning points
Must link to explicitly stated x
values or coordinates
Condone incorrect y values for
any coordinates given | 2.2a | R1
Subtotal | 3
Q | Marking instructions | AO | Marks | Typical solution
--- 11(b) ---
11(b) | Identifies one correct increasing
region | 2.4 | M1 | x < 1, x > 4
Obtains x < 1, x > 4
Accept x≤1, x≥4 | 2.1 | R1
Subtotal | 2
Question 11 Total | 5
Q | Marking instructions | AO | Marks | Typical solution
It is given that for the continuous function $g$

• $g'(1) = 0$

• $g'(4) = 0$

• $g''(x) = 2x - 5$

\begin{enumerate}[label=(\alph*)]
\item Determine the nature of each of the turning points of $g$

Fully justify your answer.
[3 marks]

\item Find the set of values of $x$ for which $g$ is an increasing function.
[2 marks]
\end{enumerate}

\hfill \mbox{\textit{AQA AS Paper 1 2024 Q11 [5]}}